Question

如何将char 缓冲区转换为unsigned short int newBuffer？以下是我的代码：

另外，在生成的newbuffer中，如何获得大小。我正在char 缓冲区中读取一个Image文件，为了进一步处理，我想将此char 转换为unsigned short int *。请有人帮我解决这个问题

FILE * pFile;
long lSize;
char * buffer;
size_t result;
pFile = fopen ( "d:\\IMG1" , "rb" );
if (pFile==NULL) {fputs ("File error",stderr); exit (1);}
// obtain file size:
fseek (pFile , 0 , SEEK_END);
lSize = ftell (pFile);
rewind (pFile);
// allocate memory to contain the whole file:
buffer = (char*) malloc (sizeof(char)*lSize);
if (buffer == NULL) {fputs ("Memory error",stderr); exit (2);}
// copy the file into the buffer:
result = fread (buffer,1,lSize,pFile);
if (result != lSize) {fputs ("Reading error",stderr); exit (3);}
/* the whole file is now loaded in the memory buffer. */
// terminate
fclose (pFile);

unsigned short int *shBuffer = (unsigned short int *)buffer;
int jp2shortsize = sizeof(*shBuffer); 
free (buffer);

Answer 1

最好在C ++中使用reinterpret_cast来进行指针转换：

unsigned short int* ptrA = reinterpret_cast<unsigned short int*>(ptrB);

对于大小，您已经获得了它，因此您只需要规范化您要转换为的类型的大小：

int jp2shortsize = lSize * sizeof(char) / sizeof(unsigned short int);

Answer 2

fread函数不需要char缓冲区，它接受void *，所以你不需要强制转换：

size_t const jp2shortsize = lSize / sizeof(unsigned short int);
unsigned short int * shBuffer = (unsigned short int *) malloc(sizeof(unsigned short int) * jp2shortsize);
result = fread(shBuffer, sizeof(unsigned short int), jp2shortsize, pFile); // mind endianess here

c ++ - 如何将char * buffer转换为unsigned short int * bufferSh

2 个答案: