Question

我正在尝试使用php发送多封电子邮件。但每次我尝试发送电子邮件时，我都会收到“errorerrorerror” - 每个电子邮件中的“错误” - 表中的内容。这是代码

$emailsql = "SELECT Username FROM Companyuserinfo WHERE Company_ID = '$cid'";
$emailquery = mysqli_query($connection, $emailsql);


while($emailrow = mysqli_fetch_array ($emailquery)){  
 $Usernamesend = $emailrow['Username'];

$sendsql = "SELECT * FROM users WHERE username = '$Usernamesend'";
$sendquery = mysqli_query($connection, $sendsql);

$sendrow = mysqli_fetch_array ($sendquery);
    $emailtosend = $sendrow['email'];

    $to="$emailtosend";
    $from = "info@site.org";
    $subject="TEST!";
    $message="HEY MY BROTHER!! I AM TESTING TdfdHIS BABY! WOOHOO!";
    $headers = "From: $from\n";
        $headers .= "MIME-Version: 1.0\n";
        $headers .= "Content-type: text/html; charset=iso-8859-1\n";
     mail($to, $subject, $message, $headers);

     if (!mail($to, $subject, $message, $headers)){
     echo "error";
     }
     else{
         echo "Form submitted successfully! Press back $emailtosend";
}
}

Answer 1

我让它工作....用这个替换了我以前的脚本;

$emailsql = "SELECT * FROM Companyuserinfo WHERE Company_ID = '$cid'";
$email_query = mysqli_query($connection, $emailsql);
while($emailrow = mysqli_fetch_array ($email_query)){
 $Usernamesend = $emailrow['Username'];
$company_name = $emailrow['Company_Name'];
$sendsql = "SELECT * FROM users WHERE username = '$Usernamesend'";
$send_query = mysqli_query($connection, $sendsql);
$mail_body = '';
$sendrow = '';
$sendrow = mysqli_fetch_array($send_query);
    $email = $sendrow["email"];
    $name = $sendrow["first_name"];

    $to = "$email";                          
        $from = "info@mysite.com";
        $subject = "TESTINGG";
        $message = 'TEST!!';
        $headers = "From: $from\n";
        $headers .= "MIME-Version: 1.0\n";
        $headers .= "Content-type: text/html; charset=iso-8859-1\n";
        $headers .= "X-Priority: 1 (Highest)\n";
        $headers .= "X-MSMail-Priority: High\n";
        $headers .= "Importance: High\n";
        $mail_result = mail($to, $subject, $message, $headers);
}       
        if ($mail_result) {
        echo "Submitted Successfully! Press close";
    } else {
       echo "There was an error submitting... Press close";
    }

Answer 2

mail($to, $subject, $message, $headers);
if (!mail($to, $subject, $message, $headers)){
   echo "error";
}

在if语句中，它正在运行mail()函数。删除以前的函数，并将其保留在if语句中。

尝试：

//mail($to, $subject, $message, $headers);
if (!mail($to, $subject, $message, $headers)){
   echo "error";
}

Answer 3

您的代码存在逻辑错误，这是一个建议的修复程序。

$error_cnt = 0;
$emailsql = "SELECT Username FROM Companyuserinfo WHERE Company_ID = '$cid'";
$emailquery = mysqli_query($connection, $emailsql);
$from = "info@hesnet.org";
$subject="TEST!";
$message="HEY MY BROTHER!! I AM TESTING TdfdHIS BABY! WOOHOO!";
$headers = "From: $from\n";
$headers .= "MIME-Version: 1.0\n";
$headers .= "Content-type: text/html; charset=iso-8859-1\n";
while($emailrow = mysqli_fetch_array ($emailquery)){  
  $Usernamesend = $emailrow['Username'];
  $sendsql = "SELECT * FROM users WHERE username = '$Usernamesend'";
  $sendquery = mysqli_query($connection, $sendsql);
  $sendrow = mysqli_fetch_array ($sendquery);
  if (!mail($sendrow['email'], $subject, $message, $headers)){
    $error_cnt++;
    break; // (optional) stop the loop when error is encountered.
  }
}
if($error_cnt === 0) {
  echo "Form submitted successfully! Press back $emailtosend";
} else {
  echo $error_cnt . ' error(s) occurred.';
}

备注：如果您的SMTP服务器需要身份验证，mail()不支持身份验证。尝试使用PHPMailer或SwiftMailer进行身份验证和/或附件支持。

另请注意，$emailsql使用Company_ID字段的单引号。如果是整数，则不需要单引号。

接下来，考虑通过连接表（如果可能）将2个SQL语句合并为一个。

最后，通过在循环中设置变量来略微提高性能，以避免重新创建相同内容的变量。

使用PHP一次发送多封电子邮件

3 个答案: