Question

http://developer.dnb.com/docs/2.0/common/authentication-process

我尝试访问的服务的身份验证过程在上面的url中解释。这是一个简单的REST身份验证过程，其中user-id和password传递如下：

POST https://maxcvservices.dnb.com/rest/Authentication
x-dnb-user: MyUsername
x-dnb-pwd: MyPassword

我尝试过以下代码，但收到了HTTP/1.1 400 ERROR。我无法弄清楚我做错了什么，因为我对Java和HttpClient特别陌生。任何帮助将不胜感激。

到目前为止，我尝试了以下代码：

public static void main(String[] args) throws Exception {
        CloseableHttpClient httpclient = HttpClients.createDefault();
        try {
            HttpPost httpPost = new HttpPost("https://maxcvservices.dnb.com/rest/Authentication");
            List <NameValuePair> nvps = new ArrayList <NameValuePair>();
            nvps.add(new BasicNameValuePair("x-dnb-user", "myusername"));
            nvps.add(new BasicNameValuePair("x-dnb-pwd", "mypassword"));
            httpPost.setEntity(new UrlEncodedFormEntity(nvps));
            CloseableHttpResponse response2 = httpclient.execute(httpPost);

            try {
                System.out.println(response2.getStatusLine());
                HttpEntity entity2 = response2.getEntity();
                // do something useful with the response body
                // and ensure it is fully consumed
                EntityUtils.consume(entity2);
            } finally {
                response2.close();
            }
        } finally {
            httpclient.close();
        }
    }

Answer 1

您需要将用户名和密码设置为http标头

            httPost.addHeader("x-dnb-user", "myusername");
            httPost.addHeader("x-dnb-pwd", "mypassword");

因为它需要http头文件中的那些

Answer 2

您可以在Java中使用Jersey - RESTful Web Services。

下载Jersey。

Client client = Client.create();
    String auth = new String(Base64.encode("UserName:Password"));
   String url = "https://maxcvservices.dnb.com/rest/Authentication";
    WebResource webResource = client
           .resource(url);
    ClientResponse response = webResource.header("Authorization", "Basic " + auth).type(MediaType.APPLICATION_JSON_TYPE).accept("application/json").get(ClientResponse.class);

   if (response.getStatus() != 200) {
        throw new RuntimeException("Failed : HTTP error code : "
                + response.getStatus());
    }

    String output = response.getEntity(String.class);
    System.out.println(output);

更改用户名和密码。

Answer 3

 public static void main(String[] args) throws Exception {
        CloseableHttpClient httpclient = HttpClients.createDefault();
        try {
//          
            HttpPost httpPost = new HttpPost("https://maxcvservices.dnb.com/rest/Authentication");
            httpPost.setHeader("x-dnb-user","myusername");
            httpPost.setHeader("x-dnb-pwd","mypassword");
            //List <NameValuePair> nvps = new ArrayList <NameValuePair>();
            //nvps.add(new BasicNameValuePair("x-dnb-user", "myusername"));
            //nvps.add(new BasicNameValuePair("x-dnb-pwd", "mypassword"));
            //httpPost.setEntity(new UrlEncodedFormEntity(nvps));
            CloseableHttpResponse response2 = httpclient.execute(httpPost);

            try {
                System.out.println(response2.getStatusLine());
                HttpEntity entity2 = response2.getEntity();
                // do something useful with the response body
                // and ensure it is fully consumed
                EntityUtils.consume(entity2);
            } finally {
                response2.close();
            }
        } finally {
            httpclient.close();
        }
    }

显然用户名和密码应该在HttpPost请求中使用Header传递（虽然我不知道这个设计选择的优点或安全含义是什么），这是上面的以下两行代码实现：

 httpPost.setHeader("x-dnb-user","myusername");
 httpPost.setHeader("x-dnb-pwd","mypassword");

Answer 4

d＆amp; b文档说用户名和密码应该在请求标头中发送，但是你的代码是在正文中发送它们。

不是将它们作为名称/值对添加到实体中，而是将它们设置为请求标头，例如

httpPost.setHeader("x-dnb-user", "my username");

我试图使用HTTPClient进行简单的身份验证请求，但收到错误

4 个答案: