如何为ListView中的特定项强制设置Activated = false

Question

我有点困惑如何解释这一点。让我试试。

我实施了一个导航抽屉。我通过在选择器中使用state_activated来实现所选项目的突出显示背景。

MENU_SELECTOR：

<selector xmlns:android="http://schemas.android.com/apk/res/android">
    <item android:state_pressed="true" android:drawable="@drawable/menu_active" />
    <item android:state_activated="true" android:drawable="@drawable/menu_active" />
    <item android:drawable="@drawable/menu_normal" />
</selector>

但我希望抽屉中的第3个项目始终保持正常背景。那么，是否可以从此menu_selector中仅排除第3项？

以下是抽屉的代码

public void displayView(int position) {
        Fragment fragment = null;
        switch (position) {
        case 0:
            fragment = new MainFragment();
            break;
        case 1:
            fragment = new BookListFragment();
            break;
        case 2:
            openCredit(); // THIS WILL JUST OPEN A DIALOG, HENCE I DON'T WANT IT TO KEEP HIGHLIGHTED BACKGROUND
            break;
        default:
            break;
        }
        if (fragment != null) {
            FragmentManager fragmentManager = getFragmentManager();
            fragmentManager.beginTransaction()
                    .replace(R.id.frame_container, fragment, "frag_"+position).commit();
            mDrawerList.setItemChecked(position, true);
            mDrawerLayout.closeDrawer(drawer);
        }
    }

LISTVIEW XML

<ListView
    android:choiceMode="singleChoice"
    android:listSelector="@drawable/menu_selector" />