Question

我正在使用下面这个简单的代码发送http请求：

import java.net.*;
import java.io.*;

public class URLConnectionReader {
 public static void main(String[] args) throws Exception {
    URL yahoo = new URL("http://www.yahoo.com/");
    URLConnection yc = yahoo.openConnection();
    BufferedReader in = new BufferedReader(
                            new InputStreamReader(
                            yc.getInputStream()));
    String inputLine;

    while ((inputLine = in.readLine()) != null) 
        System.out.println(inputLine);
    in.close();
 }
}

但它不起作用。我总是犯同样的错误：

 Exception in thread "main" java.net.ConnectException: Connection timed out: connect
at java.net.DualStackPlainSocketImpl.connect0(Native Method)
at java.net.DualStackPlainSocketImpl.socketConnect(Unknown Source)
at java.net.AbstractPlainSocketImpl.doConnect(Unknown Source)
at java.net.AbstractPlainSocketImpl.connectToAddress(Unknown Source)
at java.net.AbstractPlainSocketImpl.connect(Unknown Source)
at java.net.PlainSocketImpl.connect(Unknown Source)
at java.net.SocksSocketImpl.connect(Unknown Source)
at java.net.Socket.connect(Unknown Source)
at java.net.Socket.connect(Unknown Source)
at sun.net.NetworkClient.doConnect(Unknown Source)
at sun.net.www.http.HttpClient.openServer(Unknown Source)
at sun.net.www.http.HttpClient.openServer(Unknown Source)
at sun.net.www.http.HttpClient.<init>(Unknown Source)
at sun.net.www.http.HttpClient.New(Unknown Source)
at sun.net.www.http.HttpClient.New(Unknown Source)
at sun.net.www.protocol.http.HttpURLConnection.getNewHttpClient(Unknown Source)
at sun.net.www.protocol.http.HttpURLConnection.plainConnect(Unknown Source)
at sun.net.www.protocol.http.HttpURLConnection.connect(Unknown Source)
at sun.net.www.protocol.http.HttpURLConnection.getInputStream(Unknown Source)

我的操作系统：Windows 7.
我找不到问题出在哪里。我没有互联网连接问题。我已经试过通过我的防火墙，但它没有解决问题。我认为这不是网络问题，因为我有类似的c＃代码可行。

Answer 1

检查防火墙设置。

Answer 2

如果您的问题与mine类似，则问题可能是另一端的网络安全设置（无论您在哪里尝试与之交谈），而不是您自己的防火墙。

Answer 3

如果您使用Avast作为防病毒软件，此链接应该可以帮助您http://forum.avast.com/index.php?topic=120600.0

在Java中发送HTTP请求时的连接超时

3 个答案: