MySQL更新,跳过PDO的空白字段

时间:2014-01-01 07:19:11

标签: php mysql forms pdo

我想通过下面的表单更新MySQL行。表单效果很好但是,如果我将字段留空,它会将MySQL中的字段更改为空白。我想更新sql但跳过任何空白的字段。

我已经阅读了几种方法,但它们似乎不符合逻辑。即在sql字符串本身中使用if语句。 (让MySQL完成应该在PHP中完成的工作)。

if($_SERVER['REQUEST_METHOD'] != 'POST')
{   
 echo '<form method="post" action="">
    ID: <input type="text" name="a" /><br>
    Program: <input type="text" name="b" /><br>
    Description: <textarea row="6" cols="50" name="c"></textarea><br>
    Cost: <input type="text" name="d"><br>
    <input type="submit" value="Add Link" />
 </form>';
}


try {
  $dbh = new PDO($dsn, $user, $pass);
  $dbh->setAttribute( PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION );
  $stmt = $dbh->prepare('UPDATE links SET Program = :program , Descr = :descr, Cost = :cost WHERE Id= :id');

  $stmt->bindParam(":id", $_POST["a"]);
  $stmt->bindParam(":program", $_POST["b"]);
  $stmt->bindParam(":descr", $_POST["c"]);
  $stmt->bindParam(":cost", $_POST["d"]);
  $stmt->execute();
  if (!$stmt) {
    echo "\nPDO::errorInfo():\n";
    print_r($dbh->errorInfo());}
    $dbh = null;

  }
}catch (PDOException $e) {
  print "Error!: " . $e->getMessage() . "<br/>";
  die();
}

4 个答案:

答案 0 :(得分:4)

这样的事情应该有效

.
.
.
$q = array();
if(trim($_POST["b"]) !== ""){
    $q[] = "Program = :program";
}
if(trim($_POST["c"]) !== ""){
    $q[] = "Descr = :descr";
}
if(trim($_POST["d"]) !== ""){
    $q[] = "Cost = :cost";
}
if(sizeof($q) > 0){//check if we have any updates otherwise don't execute
    $query = "UPDATE links SET " . implode(", ", $q) . " WHERE Id= :id";
    $stmt = $dbh->prepare($query);
    $stmt->bindParam(":id", $_POST["a"]);
    if(trim($_POST["b"]) !== ""){
        $stmt->bindParam(":program", $_POST["b"]);
    }
    if(trim($_POST["c"]) !== ""){
        $stmt->bindParam(":descr", $_POST["c"]);
    }
    if(trim($_POST["d"]) !== ""){
        $stmt->bindParam(":cost", $_POST["d"]);
    }
    $stmt->execute();
}
.
.
.

答案 1 :(得分:1)

更改声明:

$stmt = $dbh->prepare('UPDATE links SET Program = :program , Descr = :descr, Cost = :cost WHERE Id= :id');

如下:

$stmt = $dbh->prepare('UPDATE links SET Program = IF(trim(:program)="", Program, :program) , Descr = IF(trim(:descr)="", Descr, :descr), Cost = IF(trim(:cost)="", Cost, :cost) WHERE Id= :id');

答案 2 :(得分:0)

检查帖子字段为空: 如果任何字段数据为空,它将跳过更新查询。

If( $_POST["a"] && $_POST["b"] && $_POST["c"] && $_POST["d"]){

        try {
          $dbh = new PDO($dsn, $user, $pass);
          $dbh->setAttribute( PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION );
          $stmt = $dbh->prepare('UPDATE links SET Program = :program , Descr = :descr, Cost = :cost WHERE Id= :id');

          $stmt->bindParam(":id", $_POST["a"]);
          $stmt->bindParam(":program", $_POST["b"]);
          $stmt->bindParam(":descr", $_POST["c"]);
          $stmt->bindParam(":cost", $_POST["d"]);
          $stmt->execute();
          if (!$stmt) {
            echo "\nPDO::errorInfo():\n";
            print_r($dbh->errorInfo());}
            $dbh = null;

          }
        }catch (PDOException $e) {
          print "Error!: " . $e->getMessage() . "<br/>";
          die();
        }


    }

Option2更新除空之外的所有字段:

try {
            $sql ="UPDATE links SET ";
            if($_POST["a"])
                $sql .=" Program = :program ,";
            if($_POST["b"])
                $sql .=" Descr = :descr ,";
            if($_POST["c"])
                $sql .=" Cost = :cost ,";

            $sql = rtrim($sql,',');
            $dbh = new PDO($dsn, $user, $pass);
            $dbh->setAttribute( PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION );
            $stmt = $dbh->prepare($sql);
            if($_POST["a"])
                $stmt->bindParam(":id", $_POST["a"]);
            if($_POST["b"])
                $stmt->bindParam(":program", $_POST["b"]);
            if($_POST["c"])
                $stmt->bindParam(":descr", $_POST["c"]);

            $stmt->execute();

            if (!$stmt) {
                echo "\nPDO::errorInfo():\n";
                print_r($dbh->errorInfo());}
            $dbh = null;

        }
        catch (PDOException $e) {
    print "Error!: " . $e->getMessage() . "<br/>";
    die();
}

答案 3 :(得分:0)

在PDO中使用未命名参数进行动态查询并将其作为数组传递到execute()更容易。除非至少有1个参数与id一起传递,否则不会执行该语句。我已经离开了派生语句的回声和数组的转储。

示例陈述

UPDATE `links` SET `Program` = ? , `Cost` = ? WHERE `Id` = ? 

示例数组

Array ( [0] => 2 [1] => 3 [2] => 2 )


if(isset($_GET['a'])){
$id = $_GET['a'];
$program = isset($_GET['b']) ? $_GET['b'] : NULL;
$descr = isset($_GET['c']) ? $_GET['c'] : NULL;
$cost= isset($_GET['d']) ? $_GET['d'] : NULL;
$params =array();
$sql = "UPDATE `links` SET "; //SQL Stub
if (isset($program)) {
    $sql .= " `Program` = ? ,";
    array_push($params,$program);   
}
if (isset($descr)) {
    $sql .= " `Descr` = ? ,";
    array_push($params,$descr); 
}
if (isset($cost)) {
    $sql .= " `Cost` = ? ,";
    array_push($params,$cost);  
}
$sql = substr($sql, 0, -1);//Remove trailing comma
if(count($params)> 0){//Only execute if 1 or more parameters passed.
    $sql .= " WHERE `Id` = ? ";
    array_push($params,$id);
    echo $sql;//Test
    print_r($params);//Test
    $stmt = $dbh->prepare($sql);
        $stmt->execute($params);
}
}