Question

跳转到编辑3：我打算利用我在网上找到的这个。但是，我无法弄清楚适当的变量如何适用于Keys key的参数。我无法弄清楚我必须向程序发送什么类型的变量。我尝试发送Keyboard kbState = Keyboard.GetState()，但它没有用。我尝试发送kbState.GetPressedKeys()，但它表示无效。我该怎么做？

public static string ConvertKeyToChar(Keys key, bool shift) 
{ 
    switch (key) 
    { 
        case Keys.Space: return " "; 

        // Escape Sequences 
        case Keys.Enter: return "\n";     // Create a new line 
        case Keys.Tab: return "\t";       // Tab to the right 

        // D-Numerics (strip above the alphabet) 
        case Keys.D0: return shift ? ")" : "0"; 
        case Keys.D1: return shift ? "!" : "1"; 
        case Keys.D2: return shift ? "@" : "2"; 
        case Keys.D3: return shift ? "#" : "3"; 
        case Keys.D4: return shift ? "$" : "4"; 
        case Keys.D5: return shift ? "%" : "5"; 
        case Keys.D6: return shift ? "^" : "6"; 
        case Keys.D7: return shift ? "&" : "7"; 
        case Keys.D8: return shift ? "*" : "8"; 
        case Keys.D9: return shift ? "(" : "9"; 

        // Numpad 
        case Keys.NumPad0: return "0"; 
        case Keys.NumPad1: return "1"; 
        case Keys.NumPad2: return "2"; 
        case Keys.NumPad3: return "3"; 
        case Keys.NumPad4: return "4"; 
        case Keys.NumPad5: return "5"; 
        case Keys.NumPad6: return "6"; 
        case Keys.NumPad7: return "7"; 
        case Keys.NumPad8: return "8"; 
        case Keys.NumPad9: return "9"; 
        case Keys.Add: return "+"; 
        case Keys.Subtract: return "-"; 
        case Keys.Multiply: return "*"; 
        case Keys.Divide: return "/"; 
        case Keys.Decimal: return "."; 

        // Alphabet 
        case Keys.A: return shift ? "A" : "a"; 
        case Keys.B: return shift ? "B" : "b"; 
        case Keys.C: return shift ? "C" : "c"; 
        case Keys.D: return shift ? "D" : "d"; 
        case Keys.E: return shift ? "E" : "e"; 
        case Keys.F: return shift ? "F" : "f"; 
        case Keys.G: return shift ? "G" : "g"; 
        case Keys.H: return shift ? "H" : "h"; 
        case Keys.I: return shift ? "I" : "i"; 
        case Keys.J: return shift ? "J" : "j"; 
        case Keys.K: return shift ? "K" : "k"; 
        case Keys.L: return shift ? "L" : "l"; 
        case Keys.M: return shift ? "M" : "m"; 
        case Keys.N: return shift ? "N" : "n"; 
        case Keys.O: return shift ? "O" : "o"; 
        case Keys.P: return shift ? "P" : "p"; 
        case Keys.Q: return shift ? "Q" : "q"; 
        case Keys.R: return shift ? "R" : "r"; 
        case Keys.S: return shift ? "S" : "s"; 
        case Keys.T: return shift ? "T" : "t"; 
        case Keys.U: return shift ? "U" : "u"; 
        case Keys.V: return shift ? "V" : "v"; 
        case Keys.W: return shift ? "W" : "w"; 
        case Keys.X: return shift ? "X" : "x"; 
        case Keys.Y: return shift ? "Y" : "y"; 
        case Keys.Z: return shift ? "Z" : "z"; 

        // Oem 
        case Keys.OemOpenBrackets: return shift ? "{" : "["; 
        case Keys.OemCloseBrackets: return shift ? "}" : "]"; 
        case Keys.OemComma: return shift ? "<" : ","; 
        case Keys.OemPeriod: return shift ? ">" : "."; 
        case Keys.OemMinus: return shift ? "_" : "-"; 
        case Keys.OemPlus: return shift ? "+" : "="; 
        case Keys.OemQuestion: return shift ? "?" : "/"; 
        case Keys.OemSemicolon: return shift ? ":" : ";"; 
        case Keys.OemQuotes: return shift ? "\"" : "'";
        case Keys.OemPipe: return shift ? "|" : "\\";
        case Keys.OemTilde: return shift ? "~" : "`"; 
    } 

    return string.Empty; 
}

编辑：所以我在XNA的更新过程中试过这个。

var newkbState = Keyboard.GetState();
Keys[] pressedKeys = newkbState.GetPressedKeys();
newInput = null;

if (newkbState.IsKeyDown(Keys.LeftShift) || newkbState.IsKeyDown(Keys.RightShift))
{
    shiftNew = true;
}
else
{
    shiftNew = false;
}

for (int count = 0; count < pressedKeys.Length; count++)
{
    newInput += ConvertKeyToChar(pressedKeys[count], shiftNew) ;
}

if (newInput != oldInput)
{
    text2 += newInput;
}
oldInput = newInput;

现在我的问题是，如果我按住S并按下O，它将输入SOSS。无论如何我可以阻止这种情况发生吗？

EDIT2： var newkbState = Keyboard.GetState（）; newkbState = GetKeysPressedBetween（oldkbState，newkbState）; Keys [] pressedKeys; pressedKeys = newkbState.GetPressedKeys（）;

            if (newkbState.IsKeyDown(Keys.LeftShift) ||       newkbState.IsKeyDown(Keys.RightShift))
            {
                shiftNew = true;
            }
            else
            {
                shiftNew = false;
            }

            newInput = "";

            for (int count = 0; count < pressedKeys.Length; count++)
            {
                newInput += ConvertKeyToChar(pressedKeys[count], shiftNew);

            }

           if ((newInput != oldInput) && (newkbState != oldkbState))
            {
            text2 += newInput;
            }
           oldInput = newInput;
            oldkbState = newkbState;

好吧，我尝试了回答者的代码，现在我遇到了问题。发生的事情是： 1.只需输出字母“a”一次输出3 a。 2.当按下两个按钮时，a和b，第一个问题发生，abababababab只是在我抓住它时不断重复。如果我解决了第一个问题，我不确定第二个问题是否会解决。

Answer 1

这并没有完全解决主要问题，但它解决了代码的基本问题。

KeyboardState GetKeysPressedBetween(KeyboardState first, KeyboardState second)
{
    KeyboardState pressed = new KeyboardState();
    for (int i = 0; i < 8; i++)
    {
        FieldInfo currentStateI = typeof(KeyboardState).GetField("currentState" + i, BindingFlags.NonPublic | BindingFlags.Instance);
        uint firstCurrentStateI = (uint)currentStateI.GetValue(first);
        uint secondCurrentStateI = (uint)currentStateI.GetValue(second);
        currentStateI.SetValueDirect(__makeref(pressed), ~firstCurrentStateI & secondCurrentStateI);
    }
    return pressed;
}

此功能将为您提供KeyboardState，指示在两帧之间按下了哪些键。你需要这样的东西才能有任何明智的打字能力。

基本上你需要做的是存储最后一帧的KeyboardState，并用它来与当前帧进行比较，所以你只需在按下它后的第一帧键入一个键。 / p>

您应该可以将其与编辑中的现有代码一起使用。

XNA，我怎么知道按下了什么键？

1 个答案: