Question

所以，我试图用Laravel 4.1实现Sentry 2。我正在使用这个资源

https://github.com/rydurham/L4withSentry

一切正常，但现在我想在注册时自动将用户分配到一个组。

来自Sentry 2 Docs，

    // Find the group using the group id
    $adminGroup = Sentry::findGroupById(5);

    // Assign the group to the user
    $user->addGroup($adminGroup);

应该有效。所以我添加了这行代码权威\回购\用户\ SentryUser.php

现在代码看起来像

try {
    //Attempt to register the user. 
    $user = $this->sentry->register(array(
        'username' => e($data['username']),
        'email' => e($data['email']), 
        'password' => e($data['password'])
        ));


       // Find the group using the group id
       $adminGroup = Sentry::findGroupById(5);
      // Assign the group to the user
       $user->addGroup($adminGroup);

    //success!
            $result['success'] = true;
            $result['message'] = trans('users.created');
            $result['mailData']['activationCode'] = $user->GetActivationCode();
    $result['mailData']['userId'] = $user->getId();
    $result['mailData']['email'] = e($data['email']);
}

但这会引发错误

Non-static method Cartalyst\Sentry\Sentry::findGroupById() should not be called statically, assuming $this from incompatible context

任何人都可以光明并告诉我我做错了什么吗？在此先感谢

Answer 1

不知何故，在你使用Sentry的地方，你并没有使用它的Facade，而是使用它本身。当你通过Facade打电话给你时，你并没有真正使用静力学，它看起来就像你一样。

你有这个：

use Cartalyst\Sentry\Sentry;

在您的代码中？

好的，但如果这条线适合你：

$user = $this->sentry->register(array(
    'username' => e($data['username']),
    'email' => e($data['email']), 
    'password' => e($data['password'])
    ));

所以你已经实例化了，你肯定可以这样做：

$adminGroup = $this->sentry->findGroupById(5);

带有Sentry 2的Laravel 4将用户添加到注册组中

1 个答案: