Question

package tic.tac.toe.menu;

import javafx.application.Application;
import javafx.event.ActionEvent;
import javafx.event.EventHandler;
import javafx.scene.Scene;
import javafx.scene.control.Button;
import javafx.scene.layout.StackPane;
import javafx.stage.Stage;

public class TicTacToeMenu extends Application {

@Override
public void start(Stage primaryStage) {
    Button start = new Button();
    start.setText("How to Play?");
    start.setOnAction(new EventHandler<ActionEvent>() {
        @Override
        public void handle(ActionEvent event) {
            System.out.println("\n"+"The goal of tic-tac-toe is to get 3 of your pieces in a row vertically, horizontally, or diagonally ");
            System.out.println("To play this game click inside a square to put down your piece, you choose to be 'x' or 'o' at the start");
        }
    });

    StackPane root = new StackPane();
    root.getChildren().add(start);

    Scene scene = new Scene(root, 350, 250);

    primaryStage.setTitle("Tic-Tac-Toe");
    primaryStage.setScene(scene);
    primaryStage.show();}

public void exit(Stage primaryStage) {
    Button exit = new Button();
    exit.setText("Quit?");
    exit.setOnAction(new EventHandler<ActionEvent>() {
        public void handle(ActionEvent event) {
            System.exit(0);
        })} // this line I get the error

    StackPane root=new StackPane();
    root.getChildren().add(exit);
    Scene scene = new Scene(root, 350, 250);
    primaryStage.setScene(scene);
    primaryStage.show();
}
}

我是Java的新手，我正在尝试制作一个菜单，但是在第40行我得到一个错误，说明非法启动类型，我很困惑这意味着什么。我认为我的语法错误但不确定要修复什么。

Answer 1

从

更改代码

})} // this line I get the error

到这个

}});

您需要连续2次关闭括号：第一次完成handle方法，第二次完成EventHandler

外部近括号是完成setOnAction调用。最后用一个半冒号来完成陈述。

Answer 2

按如下方式更改exit.setOnAction来电

exit.setOnAction(new EventHandler<ActionEvent>() {
    public void handle(ActionEvent event) {
        System.exit(0);
    }
}); // NOT })}

Answer 3

将})}替换为}});。您必须按照打开它们的相反顺序关闭块。

Java非法启动类型）预期

3 个答案: