Question

这是regex删除字符并仅保留字符串中的数字。这工作正常。请阅读以下仅适用于一个案例的例子 - 即如果用户输入“4四”，则可将其转换为44。

 //1
    //with out character 
    $amount = "44"; 
    $cleanedamount = preg_replace ( '/[^0-9]+/', '',  $amount);
    var_dump($cleanedamount);
    //2
    //digit prior
    $amount1 = "44usd"; 
    $cleanedamount1 = preg_replace ( '/[^0-9]+/', '',  $amount1);
    var_dump($cleanedamount1);

    //3
    //digit later
    $amount2 = "usd44"; 
    $cleanedamount2 = preg_replace ( '/[^0-9]+/', '',  $amount2);
    var_dump($cleanedamount2);

    //4
    //how to convert "4 four" to "44"

Demo

Answer 1

试试这个：Live Demo

$input = "4 four five";
$numbers = array('0'=> 0, 'zero'=> 0, 'one'=> 1, 'two'=> 2, 'tree'=> 3, 'four'=> 4, 'five'=> 5, 'six'=> 6, 'seven'=> 7, 'eight' => 8, 'nine'=> 9);

$reg = '/[0-9]|zero|one|two|tree|four|five|six|seven|eight|nine/';
preg_match_all($reg, $input, $output);

$out = '';
foreach ($output[0] as $key=>$value){
 if (isset($numbers[$value])){
    $output[0][$key] = $numbers[$value];
    }
    $out = $out . $output[0][$key];
}

echo($out);

Answer 2

你真的必须先用str_replace替换

//4
//how to convert "4 four" to "44"
$amount2 = "44 four"; 
$amount2=str_replace("four","4",$amount2);
$amount2=str_replace("five","5",$amount2);
...
$cleanedamount2 = preg_replace ( '/[^0-9]+/', '',  $amount2);
var_dump($cleanedamount2);

Answer 3

最明显的方法是使用str_replace用数字替换字符串。例如......

$nums = [
    'one' => 1,
    'two' => 2,
    'three' => 3,
    // etc ...
];

$amount = str_replace(array_keys($nums), array_values($nums), $amount);

只保留字符串中的数字

3 个答案: