Question

我一直试图弄清楚如何将一些PHP变量打印成某些HTML。我似乎无法使单引号或双引号正确。

我从500px API中提取图像，我想将它们渲染成一个bootstrap轮播。我想要使用的变量是$photo->name（我把它放在下面的标题标签和$photo->url之间，我想放入它而不是placehold.it url。我尝试过的所有东西都给了我一个解析错误：语法错误，意外T_VARIABLE错误但是。

有人可以帮忙吗？

<?php           
      $i = 0;      
      $len = count($obj);
      foreach ($obj->photos as $photo){

        if ($i==0) {
          print '<div class="item active">
                    <div class="fill" style="background-image:url('http://placehold.it/1900x1080&amp;text=Slide One');">
                    </div>
                  <div class="carousel-caption">
                    <h1>$photo->name</h1>
                  </div>
                  </div>';
        } else {
          print "hello 2";
        }
        $i++;
      }
  ?>

Answer 1

有几种方法，使用“echo”，包括：

$world = "world";

#If you wrap your statement in double-quotes, then:
echo "Hello $world, nice to meet you.";

#If you wrap your echo statement in single-quotes, then:
echo 'Hello '.$world.', nice to meet you.';

因此，您可以考虑将代码更改为：

<?php 

  $url = 'http://placehold.it/1900x1080&amp;text=Slide One';
  $i = 0;      
  $len = count($obj);

  foreach ($obj->photos as $photo){

    if ($i==0) {

      print '<div class="item active">
                <div class="fill" style="background-image:url(\''.$url.'\');">
                </div>
              <div class="carousel-caption">
                <h1>'.$photo->name.'</h1>
              </div>
              </div>';

    } else {

      print "hello 2";

    }

    $i++;

  }

＆GT;

Answer 2

试试这个

 <?php           
          $i = 0;      
          $len = count($obj);
          foreach ($obj->photos as $photo){

            if ($i==0) {
              print '<div class="item active">
                        <div class="fill" style="background-image:url(\'http://placehold.it/1900x1080&amp;text=Slide One\');">
                        </div>
                      <div class="carousel-caption">
                        <h1>'.$photo->name.'</h1>
                      </div>
                      </div>';
            } else {
              print "hello 2";
            }
            $i++;
          }
      ?>

Answer 3

..."background-image:url(\'http://placehold.it/1900x1080&amp;text=Slide One\')"...

使用\来逃避quatition

Answer 4

使用echo并在双引号之间粘贴html5代码。例如：

echo "<div id='mydiv'>$phpvar</div>";

或用点连接变量：

    echo "<div id='mydiv'>".$phpvar."</div>";

有时错误取决于单引号或双引号。

玩得开心！（：

Answer 5

您遇到字符串转义问题，请注意以下示例：

$variable = 'my string';

echo $variable ; // my string
echo '$variable '; // $variable
echo "$variable "; // my string

$variable = 'my st'ring'; // ERROR
$variable = 'my st\'ring'; // escaped properly

echo $variable ; // my st'ring
echo '$variable '; // $variable
echo "$variable "; // my st'ring

Answer 6

<?php           
      $i = 0;      
      $len = count($obj);
      foreach ($obj->photos as $photo){

        if ($i==0) {
          print "<div class='item active'>
                    <div class='fill' style='background-image:url(\"http://placehold.it/1900x1080&amp;text=Slide One\");'>
                    </div>
                  <div class='carousel-caption'>
                    <h1>$photo->name</h1>
                  </div>
                  </div>";
        } else {
          print "hello 2";
        }
        $i++;
      }
?>

Answer 7

如果要添加变量以进行打印或回显，则必须关闭引号并在开头和结尾添加一个点。例如：

<?php
     $and = "and";
     echo "Hello ".$and." how are you?"; //prints Hello and how are you
?>

编辑：我没注意到url()之间有引号。 PHP认为字符串在那里停止。如果你想要它之后的下一个字母是字符串的一部分，你必须在它前面添加一个左斜杠：\。例如：

<?php
    echo "My teacher said "You are not listening!"."; // Even SO's editor thinks that "You are not listening!" isn't a part of the string and adds a color. It will return an erro.
    // the right way is:
    echo "My teacher said \"You are not listening!\"."; // Here you can see that the editor doesn't adds color to whatever in the quotes because it know that is is a part of the string. It prints My teacher said "You are not listening!".
?>

在你的情况下：

<?php           
      $i = 0;      
      $len = count($obj);
      foreach ($obj->photos as $photo){

        if ($i==0) {
          print '<div class="item active">
                    <div class="fill" style="background-image:url(\'http://placehold.it/1900x1080&amp;text=Slide One\');">
                    </div>
                  <div class="carousel-caption">
                    <h1>'.$photo->name.'</h1>
                  </div>
                  </div>';
        } else {
          print "hello 2";
        }
        $i++;
      }
  ?>

在html中打印php变量

7 个答案: