Question

我在类中有一个字符串，我想从另一个类访问。

我希望我的responseString课程中可以访问字符串result或onPostExecute()（来自Registration.java）。

以下是RequestTask.java，其中包含我需要的字符串：

@SuppressLint("NewApi")
class RequestTask extends AsyncTask<String, String, String>{
      //needed string
      String responseString = null;


  @Override
  protected String doInBackground(String... uri) {
      HttpClient httpclient = new DefaultHttpClient();
      HttpResponse response;

      try {
          response = httpclient.execute(new HttpGet(uri[0]));
          StatusLine statusLine = response.getStatusLine();
          if(statusLine.getStatusCode() == HttpStatus.SC_OK){
              ByteArrayOutputStream out = new ByteArrayOutputStream();
              response.getEntity().writeTo(out);
              out.close();
              String responseString = null;
              responseString = out.toString();
              Log.d("check response", responseString);



          } else{
              //Closes the connection.
              response.getEntity().getContent().close();
              throw new IOException(statusLine.getReasonPhrase());
          }
      } catch (ClientProtocolException e) {
          //TODO Handle problems..
      } catch (IOException e) {
          //TODO Handle problems..
      }
      return responseString;
  }





  public void onPostExecute(String result) {
      super.onPostExecute(result);



}



}

以下是Registration.java，我希望字符串显示在最底部的else语句中：

@SuppressLint("NewApi")
public class Registration extends Activity {

    String result2 = null;

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.register);
          TextView detail = (TextView)findViewById(R.id.resulttext);
            detail.setText(result2);
    }


    @SuppressLint("NewApi")
    public void SubmitRegistration(View view) {




           // assign text in fields to string values
           EditText first = (EditText)findViewById(R.id.first);
           String first2 = first.getText().toString();

           EditText last = (EditText)findViewById(R.id.last);
           String last2 = last.getText().toString();

           EditText display = (EditText)findViewById(R.id.display);
           String display2 = display.getText().toString();
           //calculates the number of characters in the display field
           int length2 = display2.length();


           EditText email = (EditText)findViewById(R.id.email);
           String email2 = email.getText().toString();


           EditText password = (EditText)findViewById(R.id.password);
           String password2 = password.getText().toString();


           EditText vpassword = (EditText)findViewById(R.id.vpassword);
           String vpassword2 = vpassword.getText().toString();
           //calculates the number of characters in the password field
           int length = vpassword2.length();






    // verifying the following in order:  Passwords match? A Password field is empty?  
                                        //Password and Display Name less than 6 characters long? Email contains an @ sign and a period?   
           if(!vpassword2.equals(password2))
           {
               Toast.makeText(getApplicationContext(), "Passwords do not match!", Toast.LENGTH_SHORT).show(); 


           }
           else if (password2.isEmpty() || vpassword2.isEmpty()){

               Toast.makeText(getApplicationContext(), "Password field is empty", Toast.LENGTH_SHORT).show(); 
           }
           else if (length < 6 || length2 < 6 ) {

               Toast.makeText(getApplicationContext(), "Password and Display Name must be at least 6 characters long", Toast.LENGTH_LONG).show(); 

           }

           else if (!email2.contains("@") || !email2.contains(".")){

               Toast.makeText(getApplicationContext(), "Must enter valid email address.", Toast.LENGTH_SHORT).show(); 

           }

           else {

               String asd = "http://www.alkouri.com/android/registercheck.php?first=" + first2 + "&last=" + last2 + "&dispname=" + display2 + "&email=" + email2 + "&password=" + password2;
               Toast.makeText(getApplicationContext(), froyo, Toast.LENGTH_LONG).show(); 
               //send php with all the data to server for validation and insertion into table
               new RequestTask().execute("http://www.alkouri.com/android/registercheck.php?first=" + first2 + "&last=" + last2 + "&display=" + display2 + "&email=" + email2 + "&password=" + password2 );                       



           }
   }





}

我已尝试将其设为public void但我仍然无法在Registration.java

中访问它

Answer 1

您是否尝试从请求任务覆盖onPostExecute（String result）方法：

样品：

String asd = "http://www.alkouri.com/android/registercheck.php?first=" + first2 + "&last=" + last2 + "&dispname=" + display2 + "&email=" + email2 + "&password=" + password2;
Toast.makeText(getApplicationContext(), froyo, Toast.LENGTH_LONG).show(); 
//send php with all the data to server for validation and insertion into table

RequestTast task = new RequestTask()
{
     @override
     public void onPostExecute(String result) {
        ... do something with the resut.. 
     }
}

task.execute("http://www.alkouri.com/android/registercheck.php?first=" + first2 + "&last=" + last2 + "&display=" + display2 + "&email=" + email2 + "&password=" + password2 );

Answer 2

在onPostExecute(String arg)你可以开始你的活动

@SuppressLint("NewApi")
class RequestTask extends AsyncTask<String, String, String>{
      //needed string
      String responseString = null;
     private Context mContext;

  //This is where you pass the context
  public RequestTask(Context context) {
       mContext = context;
  }


  @Override
  protected String doInBackground(String... uri) {
      HttpClient httpclient = new DefaultHttpClient();
      HttpResponse response;

      try {
          response = httpclient.execute(new HttpGet(uri[0]));
          StatusLine statusLine = response.getStatusLine();
          if(statusLine.getStatusCode() == HttpStatus.SC_OK){
              ByteArrayOutputStream out = new ByteArrayOutputStream();
              response.getEntity().writeTo(out);
              out.close();
              String responseString = null;
              responseString = out.toString();
              Log.d("check response", responseString);



          } else{
              //Closes the connection.
              response.getEntity().getContent().close();
              throw new IOException(statusLine.getReasonPhrase());
          }
      } catch (ClientProtocolException e) {
          //TODO Handle problems..
      } catch (IOException e) {
          //TODO Handle problems..
      }
      return responseString;
  }





public void onPostExecute(String result) {
    super.onPostExecute(result);
    Intent i = new Intent(mContext Registration.class);
    Bundle bundle = new Bundle();
    bundle.putString("REGISTRATION", result);
    i.putExtras(i);
    mContext.startActivity(i);
 }



}

然后，在您的注册类中执行此操作：

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);

    Bundle b = getIntent().getExtras();
    String myResult = (String) b.getString("REGISTRATION");

    setContentView(R.layout.register);
    TextView detail = (TextView)findViewById(R.id.resulttext);
    detail.setText(result2);
}

最后，当您调用RequestTaskt类时，您将传递Context through参数，例如RequestTask mTask = new RequestTask(getActivity());

将字符串（或httprequest）从一个类传递到另一个类

2 个答案: