Question

//super Class
public class B
{
  protected sum s1 = new sum();
  protected sub  s2 = new sub();
  public B()
  {
    this.con = con;
    this.d = d;
  }

  public method_demo()
  {
// code here
   }
}



public class A extends B
{
   public method_1(Connection con , Dummy d)
   {
       super(con,d) ;
   }
}

为了测试A类，首先调用超类构造函数。如何为它编写测试用例。我试图压缩超类中的字段但仍然给出了初始化错误。

Answer 1

这是我认为你想要的代码：

public class B
{
    protected sum s1 = new sum();
    protected sub s2 = new sub();

    Connection con;
    Dummy d;

    public B(Connection con, Dummy d)
    {
        this.con = con;
        this.d = d;
    }

    public method_demo()
    {

    }
}

public class A extends B
{
    //this is a constructor, because is has the same name as the class
    public A(Connection con, Dummy d)
    {
        super(con, d);
    }
    /* // This is a method, not a constructor:
    public method_1(Connection con , Dummy d)
    {
        super(con,d) ;
    }
    */
}

测试超类字段

1 个答案: