Question

如何编写sql查询

我需要像

这样的东西

Insert Into database.table (userID,credID,time) 
values 
userId = for all in (10,15,12,17,14,267,16,689,18,7659,20)
credID = for all in (1,2,3,4,5) 
time = constant (forall the same)

现在的数据库结构

用户ID，credID，时间 10,34,2013-12-12 10,54,2013-12-12

所以我必须得到

userID,credID,time
10,34,2013-12-12
10,54,2013-12-12
10,1,2013-12-12
10,2,2013-12-12
10,3,2013-12-12
10,4,2013-12-12
10,5,2013-12-12
11,1,2013-12-12
11,2,2013-12-12
11,3,2013-12-12
11,4,2013-12-12
11,5,2013-12-12
....

逻辑算法必须像

对于范围内的每个userID（10,11,12,13,14,15,16,17,18,19,20）插入带有credID值（1,2,3,4,5）的新字段

对于单个userID，我可以使用查询创建单个credID insert into database.table (userID,credID,time) values (10,1,2013-12-12) 但我需要为多个userID插入多个credID

Answer 1

尝试这种方式：

INSERT INTO table1( userID,credID,time)
SELECT x,y,'2013-12-12' 
FROM (
  SELECT 1 As x union
  SELECT 2 union
  SELECT 3 union
  SELECT 4 union
  SELECT 5
) xx
CROSS JOIN (
  SELECT 10 As y union
  SELECT 11 union
  SELECT 12 union
  SELECT 13 union
  SELECT 15 union
  SELECT 16 union
  SELECT 17 union
  SELECT 18 union
  SELECT 19 union
  SELECT 20
) yy

演示：http://www.sqlfiddle.com/#!2/8398d/1

EDIT点。

如果这两个数字列表密集，那么还有一个数字表的技巧：

CREATE TABLE numbers( x int primary key auto_increment );

INSERT INTO numbers
SELECT null FROM information_schema.columns
LIMIT 100;

CREATE TABLE   table2
  (userID int,credID int,time date);

INSERT INTO table2( userID,credID,time)
SELECT n1.x,n2.x,'2013-12-12' 
FROM numbers n1
CROSS JOIN numbers n2
WHERE n1.x BETWEEN 1 AND 5
  AND n2.x BETWEEN 10 AND 20
;

演示：http://www.sqlfiddle.com/#!9/e121d/1

EDIT点。

数字表还有另一种技巧如果要将这两个列表作为逗号分隔的字符串传递，请尝试以下查询：

CREATE TABLE numbers( x int primary key auto_increment );

INSERT INTO numbers
SELECT null FROM information_schema.columns
LIMIT 100;

CREATE TABLE   table1
  (userID int,credID int,time date);

INSERT INTO table1( userID,credID,time)
SELECT xx,yy,'2013-12-12' 
FROM (
        SELECT reverse( if( locate(',',reverse(SUBSTRING_INDEX( y, ',', x ))) > 0,
                          substr( reverse(SUBSTRING_INDEX( y, ',', x )), 1, locate(',',reverse(SUBSTRING_INDEX( y, ',', x ))) -1 ),
                          reverse(SUBSTRING_INDEX( y, ',', x ))
                     )) AS xx
        FROM (  select '1,22,333,44,51,656'  y ) q
        JOIN numbers n
        ON n.x <= length( y ) - length( replace( y, ',','')) + 1
) q1
CROSS JOIN
(
        SELECT reverse( if( locate(',',reverse(SUBSTRING_INDEX( y, ',', x ))) > 0,
                          substr( reverse(SUBSTRING_INDEX( y, ',', x )), 1, locate(',',reverse(SUBSTRING_INDEX( y, ',', x ))) -1 ),
                          reverse(SUBSTRING_INDEX( y, ',', x ))
                     )) AS yy
        FROM (  select '111,222,3333,444,54,656'  y ) q
        JOIN numbers n
        ON n.x <= length( y ) - length( replace( y, ',','')) + 1
) q2
;

演示 - ＆gt; http://www.sqlfiddle.com/#!9/83c86/1

Answer 2

这在SQL 一般中是不可能的，除非这些值范围是某些其他表的一部分。在这种情况下，您可以通过加入范围而无需任何连接键来实现 - 这将产生所需的笛卡尔积：

insert into database.table (userID,credID,time)
select userID, credID, '2011-12-12'
from (select userID
      from database.table
      where userID in (10,15,12,17,14,267,16,689,18,7659,20))
  join (select credID 
        from database.table
        where credID in (54, 34, 1, 2, 3, 4, 5))

但正如我上面所说 - 在此代码中，我们假设database.table包含所有列出的用户ID和所有credIDs 1..5。但这并不一定是阻碍 - 相反，在大多数实际情况下你需要确保存在这些值 - 不一定在你插入的表中，但通常在数据库的另一个表中（然后你必须相应地修改子查询。）

但是，如果例如，如你所说的那样，credID是 new 并且还没有包含在任何表格中，你必须使用@kordiko的方法（对他有信用）并将其合并到上面的查询中：

insert into database.table (userID,credID,time)
select userID, credID, '2011-12-12'
from (select userID
      from database.table
      where userID in (10,15,12,17,14,267,16,689,18,7659,20)) as t1
  join (select 34 as credID union 
        select 54 union
        select 1 union
        select 2 union
        select 3 union
        select 4 union
        select 5
        ) as t2

在SQL中插入多个记录，其中值是单个查询中定义范围的所有组合

2 个答案: