Question

我有以下字符串。

18,21,24,27,30,33,36,39,42,45,48,51,54,57,60,63,66,69,72,75,78,81,84,87,90,93,96,99,102,105,108,111,114,117,120,123,126,129,132,135,138,141,144,147

我想获取每5个数字并从字符串中删除如果从18到30开始，则18到30将从此字符串中删除现在的字符串，如

33,36,39,42,45,48,51,54,57,60,63,66,69,72,75,78,81,84,87,90,93,96,99,102,105,108,111,114,117,120,123,126,129,132,135,138,141,144,147

-

var allval = jQuery('.implodearrayhide').val();
       var str_split = allval.split(",");

我正在尝试此代码，但没有用户在5

后循环完成时如何删除5号

Answer 1

你可以这样使用Array.filter：

var split = allval.split(",").filter(function(i) {
    return i % 5 === 0;
});

Answer 2

我猜您正在寻找slice：

> str = "18,21,24,27,30,33,36,39,42,45,48,51,54,57,60,63,66,69,72,75,78,81,84,87,90,93,96,99,102,105,108,111,114,117,120,123,126,129,132,135,138,141,144,147"
> newstr = str.split(",").slice(5).join()
"33,36,39,42,45,48,51,54,57,60,63,66,69,72,75,78,81,84,87,90,93,96,99,102,105,108,111,114,117,120,123,126,129,132,135,138,141,144,147"

Answer 3

使用http://jsfiddle.net/k2kST/

中的array.slice(i, i+4)

我猜你要删除数组的每个第5个元素......

Answer 4

JS代码

var str = "18,21,24,27,30,33,36,39,42,45,48,51,54,57,60,63,66,69,72,75,78,81,84,87,90,93,96,99,102,105,108,111,114,117,120,123,126,129,132,135,138,141,144,147";
while (str.length > 0) {
    str = str.replace(str.split(",", 5).join(), "").replace(/^,/, "");
    console.log(str);
}

O / P

33,36,39,42,45,48,51,54,57,60,63,66,69,72,75,78,81,84,87,90,93,96,99,102,105,108,111,114,117,120,123,126,129,132,135,138,141,144,147
48,51,54,57,60,63,66,69,72,75,78,81,84,87,90,93,96,99,102,105,108,111,114,117,120,123,126,129,132,135,138,141,144,147
63,66,69,72,75,78,81,84,87,90,93,96,99,102,105,108,111,114,117,120,123,126,129,132,135,138,141,144,147
78,81,84,87,90,93,96,99,102,105,108,111,114,117,120,123,126,129,132,135,138,141,144,147
93,96,99,102,105,108,111,114,117,120,123,126,129,132,135,138,141,144,147
108,111,114,117,120,123,126,129,132,135,138,141,144,147
123,126,129,132,135,138,141,144,147
138,141,144,147

<强> JSfiddle

字符串转换数组并从字符串中删除

4 个答案:

JS代码

O / P