我想用静态函数扩展我的UserModel.model对象。我该怎么做? 正如你可以在下面看到的,我的UserModel.model是一个猫鼬模型对象,但我需要为这个对象添加方法,重点是:我不知道怎么写它。我不能像Java / C#那样使用静态{}区域来执行静态代码,我找不到编写它的方法。你呢?
例如,我想添加 exists(), connect()等方法。
///<reference path='../../lib/def/defLoader.d.ts'/>
import model = require('./Model');
export module Models {
export class UserModel extends model.Models.Model implements model.Models.IModel{
/**
* Name of the model.
* MUST start by uppercase letter!
*/
private static modelName: string = 'User';
/**
* Public readable schema as object.
*/
public static schema: any = {
/**
* User Login
*/
login: {
type: 'string',
minLength: 4,
maxLength: 16,
required: true,
notEmpty: true,
unique: true
}
};
/**
* Private schema as mongoose.Schema type.
*/
private static _schema: mongoose.Schema = new mongoose.Schema(UserModel.schema);
/**
* The mongoose model that uses the mongoose schema.
*/
public static model: mongoose.Model<any> = mongoose.model(UserModel.modelName, UserModel._schema);
/**
*************************************************************************************************
*********************************** Public (Helpers) ********************************************
*************************************************************************************************
*/
/**
* Name of the model.
* MUST start by uppercase letter!
*/
public modelName: string;
/**
* Contains the static value of the public schema as object.
* It's a helper to always get the schema, from instance or static.
*/
public schema: mongoose.Schema;
/**
* Contains the static value of the object used to manipulate an instance of the model.
* It's a helper to always get the model, from instance or static.
*/
public model: mongoose.Model<any>;
/**
* Use static values as instance values.
*/
constructor(){
super();
// Use static values as instance values.
this.modelName = UserModel.modelName;
this.schema = UserModel.schema;
this.model = UserModel.model;
}
/**
*************************************************************************************************
*********************************** Extended methods ********************************************
*************************************************************************************************
*/
}
}
感谢。
答案 0 :(得分:2)
我建议您使用标准的MongooseJS方法,通过使用statics
实例的Schema
属性向模型添加静态方法,如下所示。
module MongooseDemo {
export class Demo {
public static LoginSchema: any = {
/* User Login */
login: {
type: 'string',
minLength: 4,
maxLength: 16,
required: true,
notEmpty: true,
unique: true
}
};
public static Model : any; // static store for data
constructor() {
// there is not a concept of a static constructor in
// typescript, so static initialization code may be better else
// where
}
}
// I've made this an anonymous function that is private to the module
// It's executed immediately and initializes the "static" values of the
// class. this code could be moved into a static method of course and
// and called directly in the same way
(()=> {
// create the schema defined
var schema : any = mongoose.Schema(Demo.LoginSchema);
// add the statics before creating the model
// http://mongoosejs.com/docs/guide.html#statics
schema.statics.exists = () => {
// here's a static method
};
// create the model
Demo.Model = mongoose.Model('Demo', schema);
})();
}
由于JavaScript或Typescript中没有静态构造函数的概念,我在MongooseDemo
模块中创建了一个匿名函数来自动初始化类的静态字段。您当然可以移动代码,但一般概念应该有效。
或者,您可以在创建模型后直接将静态方法添加到模型中(同样,在匿名方法中):
Demo.Model.exists2 = () => {
// something different
};
在Mongoose中添加类方法/静态的实际代码非常简单,因为它只是将所有函数(和属性)从statics
对象实例的Schema
属性复制到新的{{ 1}}直接。所以,我提供的第二个例子在功能上等同于我提出的documented的第一种方式。