Question

我有两张桌子

studentdemo：

sid |   date        |   status
--------------------------------
10  |   2013-12-28  |   1
11  |   2013-12-28  |   1
12  |   2013-12-28  |   1
13  |   2013-12-28  |   1
10  |   2013-12-30  |   1
11  |   2013-12-30  |   1
12  |   2013-12-30  |   1
13  |   2013-12-30  |   1

spdemo：

    date    |   status
------------------------    
2013-12-28  |   cd
2013-12-29  |   wd
2013-12-30  |   cd

使用查询

SELECT *
FROM `studentdemo`
  RIGHT JOIN spdemo
    ON spdemo.date = studentdemo.date
WHERE spdemo.date BETWEEN "2013-12-28"
    AND "2013-12-30"

导致日期2013-12-29的空值：

NULL NULL NULL 2013-12-29 WD

是否可以使用sid获得输出？

sid |   date        |   status  |   date        |   status
-------------------------------------------------------
10  |   null        |   null    |   2013-12-29  |   wd
11  |   null        |   null    |   2013-12-29  |   wd
12  |   null        |   null    |   2013-12-29  |   wd
13  |   null        |   null    |   2013-12-29  |   wd

Answer 1

可以使用FULL OUTER JOIN解决。

但是目前MySQL不支持这种类型的JOIN。前段时间我写了a post关于MySQL中的FULL OUTER JOIN技巧。

Answer 2

您可以交叉连接以获取所有组合，并LEFT JOIN表格;

SELECT x.sid, table1.date, table1.status, x.date bdate, table2.status bstatus
FROM (SELECT DISTINCT table1.sid, table2.date
      FROM table1 CROSS JOIN table2) x
LEFT JOIN table1 ON x.sid=table1.sid AND x.date = table1.date
LEFT JOIN table2 ON x.date=table2.date
ORDER BY bdate, sid

An SQLfiddle to test with

在mysql中加入两个表？

2 个答案: