我想使用内部存储来存储名为WordList的自定义对象的ArrayList。
这是我的代码:
@SuppressWarnings("serial")
public class WordList extends MainActivity implements Serializable {
public String name;
public ArrayList<String> wordarray;
public ArrayList<String> definitionarray;
public WordList(String newName)
{
this.name = newName;
this.wordarray = new ArrayList<String>();
this.definitionarray = new ArrayList<String>();
}
public String getName()
{
return name;
}
private void writeObject(ObjectOutputStream out) throws IOException {
out.writeUTF(name);
out.writeObject(wordarray);
out.writeObject(definitionarray);
}
private void readObject(ObjectInputStream in) throws IOException,
ClassNotFoundException {
name = in.readUTF();
wordarray = (ArrayList<String>) in.readObject();
definitionarray = (ArrayList<String>) in.readObject();
}
}
这是主要的活动:
public class MainActivity extends Activity {
private EditText text;
private ArrayList<WordList> lists = new ArrayList<WordList>();
private TextView textview;
FileOutputStream fos;
String filePath;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
text = (EditText) findViewById(R.id.editText1);
textview = (TextView) findViewById(R.id.test);
filePath = getApplicationContext().getFilesDir().getPath().toString() + ".fileName.txt";
}
public void onClick(View view) throws FileNotFoundException {
switch (view.getId()) {
case R.id.addtoarray:
String input = text.getText().toString();
WordList list = new WordList(input);
lists.add(list);
break;
case R.id.save:
try {
File f = new File(filePath);
FileOutputStream fos = new FileOutputStream(f, true);
ObjectOutputStream oos = new ObjectOutputStream(fos);
Toast.makeText(getApplicationContext(), "Wrote " + String.valueOf(lists.size() + "objects to file!"), Toast.LENGTH_LONG).show();
oos.writeInt(lists.size());
for(int i=0; i<lists.size(); i++)
{
oos.writeObject(lists.get(i));
}
oos.close();
fos.close();
} catch (FileNotFoundException e) {
e.printStackTrace();
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
break;
case R.id.load:
File saveFile = new File(filePath);
if (saveFile.exists())
{
Toast.makeText(getApplicationContext(), "File found!",
Toast.LENGTH_SHORT).show();
try {
FileInputStream fis = new FileInputStream(saveFile);
ObjectInputStream ois = new ObjectInputStream(fis);
int num = ois.readInt();
for(int i = 0; i<num; i++)
{
WordList o = (WordList) ois.readObject();
lists.add(o);
}
fis.close();
ois.close();
} catch (FileNotFoundException e) {
e.printStackTrace();
} catch (StreamCorruptedException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
} catch (ClassNotFoundException e) {
e.printStackTrace();
}
} else {
Toast.makeText(getApplicationContext(), "File not found!",
Toast.LENGTH_SHORT).show();
}
textview.setText(lists.get(0).getName());
break;
}
}
关于Toasts,保存对象,但应用程序在阅读时遇到问题。有人可以告诉我,我在这里做错了什么吗?
答案 0 :(得分:0)
您可以分两步完成:
1.您需要能够将WordList对象转换为String对象/变量,反之亦然。您可以使用评论中的建议来解答您如何执行此操作
2.然后,您将能够使用SharedPreferences保存String对象
在您的代码中,您将执行以下操作:
1.当您需要将对象保存在内存中时,将其转换为字符串:
String my_object = GetStringFromMyObject(object_to_save);
2。然后将其保存在SharedPreferences中:
SharedPreferences prefs = PreferenceManager.getDefaultSharedPreferences(context);
SharedPreferences.Editor editor = prefs.edit();
editor.putString("my_object_key", my_object);
3。最后,您可以随时恢复该值:
MyObject object_to_restore = GetMyObjectFromString(prefs.getString("my_object_key", "default_value));