Question

我有这个属性数组，例如：

Array
(

    [0] => Array
        (
            [id] => 20
            [title] => Brown
            [parent_id] => 1
            [parent_title] => Color
            [isMultiple] => 1
        )

    [1] => Array
        (
            [id] => 21
            [title] => Cream
            [parent_id] => 1
            [parent_title] => Color
            [isMultiple] => 1
        )

    [2] => Array
        (
            [id] => 61
            [title] => S
            [parent_id] => 2
            [parent_title] => Size
            [isMultiple] => 1
        )

    [3] => Array
        (
            [id] => 62
            [title] => M
            [parent_id] => 2
            [parent_title] => Size
            [isMultiple] => 1
        )

    [4] => Array
        (
            [id] => 63
            [title] => L
            [parent_id] => 2
            [parent_title] => Size
            [isMultiple] => 1
        )

)

从这个数组我们可以理解，我们有6种库存变化：

1 | Brown | S
2 | Brown | M
3 | Brown | L
4 | Cream | S
5 | Cream | M
6 | Cream | L

循环使用此数组以创建6个变体的另一个数组的正确方法是什么，如上例所示。

让我们假设我在数组中有另外两个attrs：

[5] => Array
    (
        [id] => 64
        [title] => Cotton
        [parent_id] => 3
        [parent_title] => Metiral
        [isMultiple] => 1
    )

[6] => Array
    (
        [id] => 65
        [title] => Wool
        [parent_id] => 3
        [parent_title] => Metiral
        [isMultiple] => 1
    )

如何循环使用此数组来创建如下变体：

1 | Brown | S | wool
2 | Brown | S | cotton
3 | Brown | M | wool
4 | Brown | M | cotton
5 | Brown | L | wool
6 | Brown | L | cotton
7 | Cream | S | wool
8 | Cream | S | cotton
9 | Cream | M | wool
10 | Cream| M | cotton
11 | Cream| L | wool
12 | Cream| L | cotton

提前致谢！

Answer 1

好的，我找到了解决方案：

一个。是的，我创建了一个包含所有属性的关联数组：

阵（

[0] => Array
    (
        [0] => 20
        [1] => 21
    )

[1] => Array
    (
        [0] => 61
        [1] => 62
        [2] => 63
    )

）

B中。然后我递归地创建了所有可能的变化：

function buildVariants($arrays, $i = 0) {
if (!isset($arrays[$i])) {
    return array();
}
if ($i == count($arrays) - 1) {
    return $arrays[$i];
}

// get combinations from subsequent arrays
$tmp = $this->buildVariants($arrays, $i + 1);

$result = array();

// concat each array from tmp with each element from $arrays[$i]
foreach ($arrays[$i] as $v) {
    foreach ($tmp as $t) {
    $result[] = is_array($t) ? array_merge(array($v), $t) : array($v, $t);
    }
}

return $result;
}

℃。然后我将它添加到这个结构中的表中：

See tables stru

Answer 2

可能先从“清理”您的数据开始：

$attr = array();

foreach( $attributes as $attribute ){
  $attr[$attribute['parent_title']][] = $attribute['title'];
}

所以你有类似

的东西

array(
  "Color" => array(
    "Color1",
    "Color2",
    "Color3"
  ),
  "Size" => array(
    "Size1",
    "Size2",
    "Size3"
  ),
  //...
);

从那以后这应该是有帮助的：
How to generate in PHP all combinations of items in multiple arrays

循环属性以创建库存变化

2 个答案: