Question

我在使用ACM的Java中遇到了caesar密码的问题。这是我的代码：

import acm.program.*;

public class Ceasar extends ConsoleProgram{

  public void run() {
    println("This program encodes a
    message using a Caesar cipher.");

    int shifter=readInt("Enter the number of character positions to shift: ");
    String msg=readLine("Enter a message :");
    String Solution=encodeCaesarCipher(msg,shifter);

    println("Encoded message: "+Solution);
  }

  private String encodeCaesarCipher(String str,int shift){
    String result="";

    for (int i=0;i<str.length();i++){
      char helper=str.charAt(i);
      helper=(helper+shift);

      if (helper>'Z'||helper>'z') helper =(helper-26);
      if (helper<'A'||helper<'a') helper=(helper+26);

      result= result+helper;
    }

    return result;
  }
}

编译时我遇到这些错误：

Ceasar.java:21: error: possible loss of precision
  helper=helper+shift;
                ^
  required: char
  found: int

Ceasar.java:22: error: possible loss of precision
  if (helper>'Z'||helper>'z') helper =helper-26;
                                             ^
  required: char
  found: int

Ceasar.java:23: error: possible loss of precision
  if (helper<'A'||helper<'a') helper=helper+26;
                                            ^
  required: char
  found: int
3 errors

Answer 1

如果没有明确表示您同意可能的精度损失（溢出/下溢），则无法在Java中向int添加char。添加(char)广告代码，int与char一起使用{/ 1}}。

Answer 2

以下是您的代码的固定版本将其与您的版本进行比较以确保
你理解这些变化。

    public static void main(String[] args){
        String s = encodeCaesarCipher("abc", 5);
        System.out.println(s);
        s = encodeCaesarCipher("abc", 2);
        System.out.println(s);
        s = encodeCaesarCipher("abc", 1);
        System.out.println(s);
    }

    private static String encodeCaesarCipher(String str,int shift){
         String result="";
         for (int i=0;i<str.length();i++){
             int helper=str.charAt(i);
             helper=(helper+shift);
             if (helper>'Z'||helper>'z') helper =(helper-26);
             if (helper<'A'||helper<'a') helper=(helper+26);
                result= result+ (char)helper;
         }
         return result;
     }

输出：

fgh
cde
bcd

Java ACM中的凯撒密码

2 个答案: