Question

我有一个DB如下：

        name                ||        Country       ||   code
     Los Angeles                   United States          LAX
***Additional Services***         United Kingdom          999V
     New York                      United States          NYC

我想选择与列匹配的三列中的所有值，但隐藏以'*'开头的值。这是我的sql从三列中选择任何值，我只需要添加该部分以跳过以*开头的值。

SELECT code, name, Country FROM city_codes WHERE CONCAT(code, name, Country) LIKE '%$term%' ORDER BY name ASC

Answer 1

那么，这个怎么样？

SELECT code, name, Country
FROM city_codes
WHERE CONCAT(code, name, Country) LIKE '%$term%' and 
      code not like '*%' and name not like '*%' and country not like '*%'
ORDER BY name ASC;

Answer 2

添加到where子句

and name not like '*%'

SQL从DB中选择列，但不以'*'开头？

2 个答案: