我一直试图制作一个简单的基于平铺的游戏，我试图获得鼠标X和Y坐标。
我已成功使用此代码获取X和Y坐标
Point b;
PointerInfo a;
int x = 0;
int y = 0;
a = MouseInfo.getPointerInfo();
b = a.getLocation();
x = (int) b.getX();
y = (int) b.getY();
g.drawString("Mouse X: " + x, 5, 30);
g.drawString("Mouse Y: " + y, 5, 40);
但是，这将返回相对于鼠标所在的JFrame的x和y坐标。我要做的是使x和y相对于背景图像进行协调。
所以这里有一些数字和信息：
Jframe：1280x1024 px
背景图片：10000x10000像素
当玩家向上，向下，向左，向右移动jframe并且我在背景上叠加了一个瓦片地图时，滚动背景。我创建了一个数组，用于在生成切片时存储每个切片的值。
该数组存储3个值。平铺ID，X坐标，Y坐标。
相对于背景图片。
示例：
/////////////////////////////////////////////// ///////////////////////////////
背景：10000x10000
TILE 45198 ------ Tile X位置：9880 ------ Tile Y位置：9976
/////////////////////////////////////////////// ////////////////////////////////
所以我需要获得与背景图像相关的鼠标x和y，无论jframe在哪里，都可以用鼠标找到正确的图块。
与线性插值下面的答案有关。这是使代码更简单的代码
frame.java
/* NOTES
*
* 10000/10000 pixel map
*
* 232 tiles vertical
* 192 tiles horizontal
*
* tile Width: 43
* tile Height: 52
*/
import javax.swing.JFrame;
public class Frame {
public static void main(String[] args) {
JFrame frame = new JFrame("Isometric Game");
frame.add(new Board());
frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
frame.setSize(1280,1024);
frame.setVisible(true);
}
}
BOARD.java
public class Board extends JPanel implements ActionListener {
Character player;
Image background;
Image tile;
Timer time;
Point b;
PointerInfo a;
int check = 0;
int x = 0;
int y = 0;
int maxtiles = 100002;
int createdtiles = 0;
int ctiles = 0;
int tilex;
int tiley;
int tileid;
public static int[][] multix; // Stores the x and y Values for each tile
public Board()
{
player = new Character();
addKeyListener(new AL());
addMouseListener(new ALMOUSE());
setFocusable(true);
ImageIcon i = new ImageIcon("src/images/background.jpg"); //the location of the still image
background = i.getImage();
ImageIcon t = new ImageIcon("src/images/tile.png"); //the location of the still image
tile= t.getImage();
time = new Timer(5,this);
time.start();
a = MouseInfo.getPointerInfo();
b = a.getLocation();
}
public void actionPerformed(ActionEvent e) {
player.move();
repaint();
}
public void paint(Graphics g){
super.paint(g);
Graphics2D g2d = (Graphics2D) g;
a = MouseInfo.getPointerInfo();
b = a.getLocation();
x = (int) b.getX();
y = (int) b.getY();
g2d.drawImage(background, 1200-player.nx2, 900-player.ny2, null); //Draw Background - players positions
GetTiles(g2d);
g2d.drawImage(player.getImage(),10, 10,null);
tilex = background.getWidth(null) - background.getWidth(null);
tiley = background.getHeight(null) - background.getHeight(null);
g2d.drawImage(tile,x, y,null);
g.drawString("Background X : " + tilex, 5, 10);
g.drawString("Background Y : " + tiley, 5,20);
g.drawString("Mouse X: " + x, 5, 30);
g.drawString("Mouse Y: " + y, 5, 40);
g.drawString("Created Tiles:" + ctiles, 5, 50);
int collideget = 0;
Rectangle mouse = new Rectangle (x,y,50,50);
for (int i = 0 ; i < multix.length; i++){
Rectangle tilecollide = new Rectangle(multix[i][0],multix[i][1],52,43);
if (mouse.intersects(tilecollide)){
collideget = 1;
}
if (collideget == 1){
System.out.println(" MOUSE COLLIDED WITH TILEID:" + multix[i]);
collideget = 0;
}
}
}
private class AL extends KeyAdapter{
public void keyReleased(KeyEvent e){
player.keyReleased(e);
}
public void keyPressed(KeyEvent e){
player.keyPressed(e);
}
}
private class ALMOUSE extends MouseAdapter{
public void mouseEntered(MouseEvent e){
player.mouseEntered(e);
}
public void mouseExited(MouseEvent e){
player.mouseExited(e);
}
}
public void GetTiles(Graphics2D g2d){
multix = new int[maxtiles][2]; // Stores the x and y Values for each tile
tileid = 0;
tilex = background.getWidth(null) - background.getWidth(null);
tiley = background.getHeight(null) - background.getHeight(null);
for (int h = 0; h <= 100000 ; h++) // Create the row of tiles
{
if (tiley > 9976){
h = 100001;
}
else if (tilex > 0 && tilex <= 9984){
multix[tileid][0] = tilex; // Store X value for tile ID
multix[tileid][1] = tiley; // Store Y value for tile ID
g2d.drawImage(tile,tilex - player.nx2, tiley - player.ny2,null); // Draw Tile
tilex += tile.getWidth(null); //get next tile
createdtiles += 1; //ADD TILE
}
else if (tilex > 9984){
tilex = background.getWidth(null) - background.getWidth(null); // Reset the tile back to the original x position
tiley += tile.getHeight(null); //Add the next tile height
multix[tileid][0] = tilex; // Store X value for tile ID
multix[tileid][1] = tiley; // Store Y value for tile ID
g2d.drawImage(tile,tilex - player.nx2, tiley - player.ny2,null); // Draw Tile
createdtiles += 1; //ADD TILE
}
else if (tilex == 0){
multix[tileid][0] = tilex; // Store X value for tile ID
multix[tileid][1] = tiley; // Store Y value for tile ID
g2d.drawImage(tile,tilex - player.nx2, tiley - player.ny2,null); // Draw Tile
tilex += tile.getWidth(null); //Get next tile
createdtiles += 1; //ADD TILE
}
tileid++;
}
if (check == 0){
System.out.println(multix.length);
for (int m = 0; m <= createdtiles; m++)
{
System.out.println( "TILE " + m + " ------ Tile X location: " + multix[m][0] + " ------ Tile Y location: " + multix[m][1] );
}
check = 1;
System.out.println("MAX # OF TILES:" + maxtiles);
System.out.println("CREATED # OF TILES:" + createdtiles);
ctiles = createdtiles;
}
}
public int[][] getArray(){
return multix;
}
}
感谢您提前提供任何帮助
答案 0 :(得分：3)
top-level container可能包含不相关的装饰品。相反，使用linear interpolation相对于封闭的面板，如图here所示。
答案 1 :(得分：2)
我总是解决这样的问题的方法是让X＆amp; Y背景图像的位置，然后将其添加到相对于Jframe的鼠标位置。