Question

我有这段代码：

<ul style="list-style-type:none;">
<?php foreach ($rawmenuitems as $rawmenuitem) 
    { 
    if (in_array($rawmenuitem->note, $completedmenuitems))
    { ?>
        <li>
        <span style="color:#666666; "><?php echo ($rawmenuitem->title); ?></span>
        </li>
<?php   }
    else
    { ?>
        <li>
        <?php echo ('<a href =' . $rawmenuitem->link . '&amp;Itemid=' . $rawmenuitem->id . '">' . $rawmenuitem->title . '</a>'); ?>
        </li>
<?php   }
}?>
</ul>

数组是：

$rawmenuitems ( 
[0] => stdClass Object ( [link] => index.php?option=com_breezingforms&view=form [id] => 1378 [title] => 334 Basic Information [note] => 5 ) 
[1] => stdClass Object ( [link] => index.php?option=com_breezingforms&view=form [id] => 1381 [title] => 334 Drug Testing [note] => 17 ) 
[2] => stdClass Object ( [link] => index.php?option=com_breezingforms&view=form [id] => 1380 [title] => 334 Emergency Treatment [note] => 15 ) 
[3] => stdClass Object ( [link] => index.php?option=com_breezingforms&view=form [id] => 1379 [title] => 334 Extracurricular [note] => 7 ) 
[4] => stdClass Object ( [link] => index.php?option=com_breezingforms&view=form [id] => 1377 [title] => 334 Florida Concussion [note] => 12 ) 
[5] => stdClass Object ( [link] => index.php?option=com_breezingforms&view=form [id] => 1376 [title] => 334 Florida Consent [note] => 14 )
)

和

$completedmenuitems ( 
[0] => stdClass Object ( [id] => 1377 [note] => 12 ) 
[1] => stdClass Object ( [id] => 1376 [note] => 14 ) 
)

但是代码的输出只是六个链接，而不考虑条件的结果。有什么想法吗？

Answer 1

那些是对象数组 - 所以在数组$ completedmenuitems中没有对象“5”。有一个对象有属性note = 5.

您必须从对象中将note从数组中提取到其他数组。

$completedmenuitems_notes = array_map(
    create_function(
        '$object', 
        'return $object->note;'
    ), 
    $completedmenuitems
);

Answer 2

$rawmenuitem->note是一个整数，而$completedmenuitems是一个包含名为note的属性的对象数组。因此，in_array()将整数与对象进行比较。

这个问题有多种解决方案。一个是推出自己的功能：

function isCompletedItem($completedItems, $note) {
  foreach ($completedItems => $items) {
    if ($items->note == $note) {
      return true;
    }
  }
  return false;
}

if (in_array($completedmenuitems, $rawmenuitem->note))

in_array没有按照我的理解应该这样做

2 个答案: