Question

如果从数据库中找到数据，我需要从数据库返回$ data，但不幸的是，我的代码无法返回数据。

我尝试输入不存在的数据，它设法返回错误消息，但如果数据存在，则页面不显示任何内容。

我可以在if语句中知道我哪里出错吗？

下面是我的代码，包含$ data返回后脚本将执行。

$day  = $_POST['day']; 
$month = $_POST['month']; 
$year  = $_POST['year']; 
$dob = implode('/', array($day,$month,$year)); 

if(isset($_POST['submit'])){ 
    if(empty($_POST['day']) || empty($_POST['month']) || empty($_POST['year'])){ 
        echo "You need to fill in each field.<br /><br /><a href=\"./\" title=\"Fill In Again\">Click here to <b>fill in each field</b> again</a>"; 
    exit; 
    } 
} 

//Date that user keyin 
$userDate = $dob; 
$dateTime = DateTime::createFromFormat('d/m/Y', $userDate); 
$myFormat = $dateTime->format('Y-m-d'); 

//Query string and put it in a variable. 
if(isset($_POST['dob_chi'])){ 
    $query = "SELECT * FROM $table_n WHERE dob_chi = :date"; 
} else { 
    $query = "SELECT * FROM $table_n WHERE dob_eng = :date"; 
} 

$stmt = $db->prepare($query); 
$stmt->execute(array('date' => $myFormat)); 
$data = $stmt->fetchAll(); 
if ( !$data ) { 
    echo 'No data found in database!'; 
    exit; 
} else { 
    return $data=$userDate; 
} 

//Now we create a while loop for every entry in our DB where the date is match. 
while ($row = $stmt->fetchObject()) { 
    $r1          = $row->rowone; 
    $r2          = $row->rowtwo; 
    $r3          = $row->rowthree; 
    $englishdate = $row->dob_eng; 
    $chinesedate = $row->dob_chi; 
    $zodiac      = $row->zodiac; 

    //add all initial data into a matrix variable for easier access to them later 
    //To access rowone use $rows[0][0], rowtwo $rows[1][0] ect. 
    //The matrix is an array which contains multiple array. eg. 2-dimensional arrays 
    //To get all the variables with $r1X simply retrieve the first array of the matrix eg $rows[0] 
    $rows = array(array($r1),array($r2),array($r3),array());        
} 
//Similarities between row1 and row2 made me incorporate modulo value as an argument. 
function incmod($a, $m){ 
    return ($a % $m) + 1; 
}

感谢您的时间

Answer 1

摆脱界限：

return $data=$userDate;

因为它会结束你的脚本并覆盖$data变量。

变化：

$data = $stmt->fetchAll(PDO::FETCH_OBJ);

然后更改行：

while ($row = $stmt->fetchObject()) {

为：

foreach ($data as $row) {

$ data未返回结果

1 个答案: