我尝试使用AsyncFileUpload和按钮上传图像。下面是我用来做的代码。但它导致双重上传不确定如何只在点击btnUpload后才能上传图像。目前的问题是,一旦我在asyncfileupload控件中浏览我想要的图像,就会有一个loading.gif显示它正在加载,我刷新页面而不点击已经上传到数据库的btnUpload图像。我想要做的是只在点击btnUpload后才上传图片。帮忙解决这个问题。谢谢!
标记代码:
<script type="text/javascript" language="javascript">
function StartUpload(sender, args) {
var filename = args.get_fileName();
var path = args.get_path();
if (filename != "") {
// code to get File Extension..
var arr1 = new Array;
arr1 = filename.split("\\");
var len = arr1.length;
var img1 = arr1[len - 1];
var filext = img1.substring(img1.lastIndexOf(".") + 1);
// Checking Extension
if (filext == "jpg" || filext == "JPG") {
$get("<%=lblUpload.ClientID %>").innerHTML = "";
$get("<%=btnUpload.ClientID %>").disabled = false;
return true;
}
else {
$get("<%=lblUpload.ClientID %>").innerHTML = "Only .jpg and .JPG image allowed.";
$get("<%=btnUpload.ClientID %>").setAttribute('disabled', 'disabled');
return false;
}
}
}
<asp:AsyncFileUpload ID="AsyncFileUpload1" runat="server"
CompleteBackColor="Lime" UploaderStyle="Modern"
ErrorBackColor="Red" ThrobberID="Throbber"
OnUploadedComplete="btnUpload_Click"
UploadingBackColor="#66CCFF"
OnClientUploadStarted="StartUpload"
align="center"/>
<br />
<br />
<asp:Label ID="Throbber" runat="server" Style="display: none">
<img src="image/indicator.gif" alt="loading" />
</asp:Label>
<asp:Button ID="btnUpload" runat="server" OnClick="btnUpload_Click" Text="Upload" />
<br />
<br />
<asp:Label ID="lblUpload" runat="server" Text=""></asp:Label>
btnUpload代码:
protected void btnUpload_Click(object sender, EventArgs e)
{
if (AsyncFileUpload1.HasFile == true)
{
String nric = (String)Session["nric"];
string filePath = AsyncFileUpload1.PostedFile.FileName;
string filename = Path.GetFileName(filePath);
string ext = Path.GetExtension(filename);
string contenttype = String.Empty;
switch (ext)
{
case ".jpg":
contenttype = "image/jpg";
break;
case ".JPG":
contenttype = "image/jpg";
break;
}
if (contenttype != String.Empty)
{
System.Drawing.Image uploaded = System.Drawing.Image.FromStream(AsyncFileUpload1.PostedFile.InputStream);
System.Drawing.Image newImage = new Bitmap(1024, 768);
using (Graphics g = Graphics.FromImage(newImage))
{
g.InterpolationMode = InterpolationMode.HighQualityBicubic;
g.DrawImage(uploaded, 0, 0, 1024, 768);
}
byte[] results;
using (MemoryStream ms = new MemoryStream())
{
ImageCodecInfo codec = ImageCodecInfo.GetImageEncoders().FirstOrDefault(c => c.FormatID == ImageFormat.Jpeg.Guid);
EncoderParameters jpegParms = new EncoderParameters(1);
jpegParms.Param[0] = new EncoderParameter(Encoder.Quality, 95L);
newImage.Save(ms, codec, jpegParms);
results = ms.ToArray();
}
//insert the file into database
string strQuery = "Update MemberAccount Set profilepicture = @Data Where nric = @Nric";
SqlCommand cmd = new SqlCommand(strQuery);
cmd.Parameters.Add("@Nric", SqlDbType.VarChar).Value = nric;
cmd.Parameters.AddWithValue("@Data", results);
InsertUpdateData(cmd);
UpdatePanel2.Update();
lblUpload.ForeColor = System.Drawing.Color.Green;
lblUpload.Text = "Profile Picture Updated.";
}
}
}
答案 0 :(得分:0)
我认为只需删除下面的行就可以了。
OnUploadedComplete="btnUpload_Click"
请告诉我它是否有用......
答案 1 :(得分:0)
我认为您没有按照预期的方式使用AyncFileUpload
控件。该控件旨在自动选择文件后上传文件。 “上传”按钮的更正确的术语将是“保存”,因为它只需要保存在服务器上的文件。
通过调用OnUploadedComplete
,您实际上是在调用代码来保存文件。来自here:
UploadedComplete - 文件成功时在服务器端触发 上传
正如aliCna建议您应该删除此调用,因为它似乎是多余的。
如果您只想在单击“上传”按钮后上传文件,则需要调查其他控件,您可能需要查看其他上传控件(例如AjaxFileUpload或标准文件在ASP.net上传控件[虽然我不太确定使用更新面板的效果如何]。