Question

我有这个Oracle表：

SQL>  Name                                         Null?    Type
 ----------------------------------------- -------- ----------------------------
 JOB_ID                                    NOT NULL VARCHAR2(13)
 TYPE                                      NOT NULL NUMBER
 COMPONENT_DESCRIPTION                     NOT NULL VARCHAR2(255)
 COMPONENT_ID                                       VARCHAR2(13)
 STATUS                                    NOT NULL NUMBER(1)
 REASON                                             VARCHAR2(255)
 NOTES                                              VARCHAR2(255)

SQL>

没有定义的主键，但组合的JOB_ID，TYPE和COMPONENT_DESCRIPTION是唯一的。我不能对数据库结构进行任何更改，而我正在工作的代码只能从DB中读取，它永远不会写入它。

我制作了这个Hibernate地图文件：

<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE hibernate-mapping PUBLIC 
    "-//Hibernate/Hibernate Mapping DTD 3.0//EN" 
    "classpath://org/hibernate/hibernate-mapping-3.0.dtd">
<hibernate-mapping schema="ARCHIVE">

<class name="myclass.ArchiveJobHeaderComponents" table="JOB_HEADER_COMPONENTS">
    <composite-id>
        <key-property name="jobId" column="JOB_ID" type="java.lang.String" />
        <key-property name="type" column="TYPE" type="java.lang.Number" />
        <key-property name="componentDescription" column="COMPONENT_DESCRIPTION" type="java.lang.String" />
    </composite-id>
    <property name="componentId" column="COMPONENT_ID" type="java.lang.String" not-null="false" />
    <property name="status" column="STATUS" type="java.lang.Number" />
    <property name="reason" column="REASON" type="java.lang.String" not-null="false" />
    <property name="notes" column="NOTES" type="java.lang.String" not-null="false" />
</class>

<query name="JobHeaderComponents.lookupJobHeaderComponents">
    <![CDATA[from myclass.ArchiveJobHeaderComponents where
               jobId = :jobId and
               type = :type and
               componentDescription = :componentDescription ]]>
</query>

<query name="JobHeaderComponents.listJobHeaderComponentsByComponentId">
    <![CDATA[from myclass.ArchiveJobHeaderComponents where componentId = :id]]>
</query>

</hibernate-mapping>

这是相应的Java类文件：

package myclass;

import org.apache.commons.lang.builder.EqualsBuilder;
import org.apache.commons.lang.builder.HashCodeBuilder;
import org.apache.commons.lang.builder.ToStringBuilder;

import java.io.Serializable;
import java.lang.Number;
import java.util.HashSet;

public class ArchiveJobHeaderComponents implements Serializable {

    private String jobId;
    private Number type;
    private String componentDescription;
    private String componentId;
    private Number status;
    private String reason;
    private String notes;

    public String getJobId() {
        return jobId;
    }

    public void setJobId(String jobId) {
        this.jobId = jobId;
    }

    public Number getType() {
        return type;
    }

    public void setType(Number type) {
        this.type = type;
    }

    public String getComponentDescription() {
        return componentDescription;
    }

    public void setComponentDescription(String componentDescription) {
        this.componentDescription = componentDescription;
    }

    public String getComponentId() {
        return componentId;
    }

    public void setComponentId(String componentId) {
        this.componentId = componentId;
    }

    public Number getStatus() {
        return status;
    }

    public void setStatus(Number status) {
        this.status = status;
    }

    public String getReason() {
        return reason;
    }

    public void setReason(String reason) {
        this.reason = reason;
    }

    public String getNotes() {
        return notes;
    }

    public void setNotes(String notes) {
        this.notes = notes;
    }

    public int hashCode() {
       return new HashCodeBuilder().
                           append(getJobId()).
                           append(getType()).
                           append(getComponentDescription()).
                           append(getComponentId()).
                           append(getStatus()).
                           append(getReason()).
                           append(getNotes()).toHashCode();
    }

    public boolean equals(Object o) {
        if (this == o) {
            return true;
        }
        if (!(o instanceof ArchiveJobHeaderComponents)) {
            return false;
        }
        ArchiveJobHeaderComponents that = (ArchiveJobHeaderComponents) o;
        return new EqualsBuilder().append(this.getJobId(), that.getJobId()).
                           append(this.getType(), that.getType()).
                           append(this.getComponentDescription(), that.getComponentDescription()).
                           append(this.getComponentId(), that.getComponentId()).
                           append(this.getStatus(), that.getStatus()).
                           append(this.getReason(), that.getReason()).
                           append(this.getNotes(), that.getNotes()).isEquals();
    }

    public String toString() {
        return new ToStringBuilder(this).
                           append("jobId", getJobId()).
                           append("type", getType()).
                           append("componentDescription", getComponentDescription()).
                           append("componentId", getComponentId()).
                           append("status", getStatus()).
                           append("reason", getReason()).
                           append("notes", getNotes()).toString();
    }

}

每当我从查询中获取数据时，我都会得到“无法反序列化”，然后出现“EOFException”错误。

我已经检查过了：
- 序列化类型的Java类中没有变量 - Java类正在实现Serializable

我不想将三列（JOB_ID，TYPE和COMPONENT_DESCRIPTION）拆分为单独的“Id”类，因为我对如何访问数据存在概念上的问题。（我意识到这不是推荐但是支持）。

任何人都可以指出我在实施这个方面做错了吗？

由于

编辑：
我已经将hbm.xml更改为没有复合键，只是JOB_ID上的id而没有任何改进我已将not-null =“false”添加到可以为空的列中，也没有改进。

Answer 1

实际上，看一下代码和Hibernate映射文件，我认为问题是你试图将列TYPE和STATUS映射到Number。 Number是一个抽象类，因此无法直接实例化。

由于TYPE和STATUS都是NOT NULL，我会使用原始Java类型来存储它们的值，例如：

public class ArchiveJobHeaderComponents implements Serializable {

  private String jobId;
  private int type; // int should give you a large enough range - but change to long if required
  private String componentDescription;
  private String componentId;
  private boolean status; // status appears to be a boolean (NUMBER(1))
  private String reason;
  private String notes;
  // remainder omitted
}

另外，请记得更新Hibernate映射文件以反映上面的内容!!

Answer 2

如果其他人正在使用传统的Hibernate（3.0）应用程序，导致此错误的其他因素是使用Java 8和OJDBC 1.4运行应用程序。升级到OJDBC 6解决了它。

Hibernate无法反序列化错误

2 个答案: