Question

当我运行此代码时，我收到一条错误消息，说该文件不存在，我创建了该文件并通过从保存部分复制目录链接回来。我也可以看到该文件，并检查了三个名称等，但是如果有人帮忙，它仍然无效。

from tkinter import *
import os.path
master= Tk()
master.geometry('500x500+0+0')



def print_value(val):
    print ("c1="+str (c1v.get()))
    print ("c2="+str(c2v.get()))


c1v=DoubleVar()
c2v=DoubleVar()


c1 = Scale(master, from_=255, to=0, length =400,width =100, troughcolor = 'blue',command=print_value, variable =c1v)
c1.grid(row=1,column=1)
c2 = Scale(master, from_=255, to=0, length =400,width =100, troughcolor = 'blue',command=print_value, variable =c2v)
c2.grid(row=1,column=2)


def func():
    pass
    file1 = open("C:/Users/Josh Bailey/Desktop/pi_dmx/preset_test.txt")
    val1, val2 = (x.split("=")[1] for x in file1)
    c1.set(val1)
    c2.set(val2)
    file1.close()


def record():

    save_path = 'C:/Users/Josh Bailey/Desktop/pi_dmx'
    name_of_file = ("preset_test ")
    completeName = os.path.join(save_path, name_of_file+".txt")
    file1 = open(completeName , "w")
    toFile = ("c1="+str (c1.get())+ "\n""c2="+str(c2.get()))
    file1.write(toFile)
    file1.close()
    master.mainloop()

rec=Button(master, text="Record",width=20, height=10, bg='Red', command=record)
rec.grid(row=2, column=1)

load=Button(master, text="Load",width=20, height=10, bg='gold',command=func)
load.grid(row=2, column=2)

错误是 -

Exception in Tkinter callback Traceback (most recent call last):  
 File "C:\Python33\lib\idlelib\run.py", line 121, in main
     seq, request = rpc.request_queue.get(block=True, timeout=0.05)   File "C:\Python33\lib\queue.py", line 175, in get
     raise Empty queue.Empty

During handling of the above exception, another exception occurred:

 Traceback (most recent call last):   File
 "C:\Python33\lib\tkinter\__init__.py", line 1475, in __call__
     return self.func(*args)   File "C:\Users\Josh Bailey\Desktop\save test.py", line 24, in func
     file1 = open("C:/Users/Josh Bailey/Desktop/pi_dmx/preset_test.txt") FileNotFoundError: [Errno 2]
No such file or directory: 'C:/Users/Josh Bailey/Desktop/pi_dmx/preset_test.txt'

Answer 1

在func内，您将文件路径指定为：

C:/Users/Josh Bailey/Desktop/pi_dmx/preset_test.txt

但是，您的record功能会使其成为：

C:/Users/Josh Bailey/Desktop/pi_dmx/preset_test .txt
#                   Note the extra space here--^

因此，Python将无法找到该文件。

要解决此问题，请在record：

中删除此行上的空格

name_of_file = ("preset_test ")
#                     here--^

现在记录将创建文件路径应该是它应该的。

此外，pass内func不应该在那里。它什么都不做。

Answer 2

你在Windows上吗？用反斜杠替换斜杠\，并在字符串的前面添加一个“r”，如下所示：

file1 = open(r"C:\Users\Josh Bailey\Desktop\pi_dmx\preset_test.txt")

希望这有效

从.txt文件加载，没有文件目录

2 个答案: