表2

Question

我需要编写查询以找出新用户和普通用户。

新用户是那些uuid在table2过去24小时内（从现在开始减去查询被触发的时间）出现的用户

。

普通用户是那些uuid在最后一天出现在table2并且在过去3天内至少也出现过一次的人。

除此之外，只考虑id > 10和ip != 2的记录。

table1是一个包含日期的临时表。我无法弄清楚如何通过连接来实现这一目标。请帮帮我。

表2

    +----+---------------------+------+------+
    | id | ts                  | uuid | ip   |
    +----+---------------------+------+------+
    |  1 | 2010-01-10 00:00:00 | uid1 |    5 |
    |  2 | 2010-01-10 00:00:00 | uid2 |   14 |
    |  3 | 2010-01-10 00:00:00 | uid3 |   11 |
    |  4 | 2010-01-11 00:00:00 | uid4 |   16 |
    |  5 | 2010-01-11 00:00:00 | uid5 |    4 |
    |  6 | 2010-01-13 00:00:00 | uid6 |    2 |
    |  7 | 2010-01-10 00:00:00 | uid1 |    1 |
    |  8 | 2010-01-11 00:00:00 | uid2 |   10 |
    |  9 | 2010-01-12 00:00:00 | uid1 |    1 |
    | 10 | 2010-01-13 00:00:00 | uid4 |    1 |
    | 11 | 2010-01-09 21:00:00 | uid1 |    1 |
    | 12 | 2010-01-09 21:30:00 | uid1 |    2 |
    | 13 | 2010-01-10 05:00:00 | uid2 |    3 |
    | 14 | 2010-01-10 12:00:00 | uid1 |    1 |
    | 15 | 2010-01-10 12:00:00 | uid3 |    1 |
    | 16 | 2010-01-10 21:00:01 | uid1 |    7 |
    | 17 | 2010-01-11 01:00:00 | uid2 |   14 |
    | 18 | 2010-01-11 05:00:00 | uid2 |   11 |
    | 19 | 2010-01-11 17:59:00 | uid4 |   13 |
    | 20 | 2010-01-11 06:00:00 | uid5 |   12 |
    | 21 | 2010-01-11 18:01:00 | uid1 |   14 |
    | 22 | 2010-01-12 23:05:00 | uid4 |   17 |
    | 23 | 2010-01-13 12:01:23 | uid6 |   13 |
    +----+---------------------+------+------+
    23 rows in set (0.00 sec)

表1

    +------------+
    | ts         |
    +------------+
    | 2010-01-10 |
    | 2010-01-11 |
    | 2010-01-12 |
    | 2010-01-13 |
    +------------+
    4 rows in set (0.00 sec)

新用户在18:00

时输出

+------------+-------+
| ts         | users |
+------------+-------+
| 2010-01-10 |     3 |
| 2010-01-11 |     2 |
| 2010-01-12 |     0 |
| 2010-01-13 |     1 |
+------------+-------+
4 rows in set (0.00 sec)

MySQL表转储

DROP TABLE IF EXISTS `table1`;
/*!40101 SET @saved_cs_client     = @@character_set_client */;
/*!40101 SET character_set_client = utf8 */;
CREATE TABLE `table1` (
  `ts` date NOT NULL
) ENGINE=MyISAM DEFAULT CHARSET=latin1;
/*!40101 SET character_set_client = @saved_cs_client */;

INSERT INTO `table1` VALUES ('2010-01-10'),('2010-01-11'),('2010-01-12'),('2010-01-13');

DROP TABLE IF EXISTS `table2`;
CREATE TABLE `table2` (
  `id` int(11) NOT NULL AUTO_INCREMENT,
  `ts` datetime DEFAULT NULL,
  `uuid` varchar(20) DEFAULT NULL,
  `ip` int(11) DEFAULT NULL,
  PRIMARY KEY (`id`)
) ENGINE=MyISAM AUTO_INCREMENT=24 DEFAULT CHARSET=latin1;
/*!40101 SET character_set_client = @saved_cs_client */;

INSERT INTO `table2` VALUES (1,'2010-01-10 00:00:00','uid1',5),(2,'2010-01-10 00:00:00','uid2',14),(3,'2010-01-10 00:00:00','uid3',11),(4,'2010-01-11 00:00:00','uid4',16),(5,'2010-01-11 00:00:00','uid5',4),(6,'2010-01-13 00:00:00','uid6',2),(7,'2010-01-10 00:00:00','uid1',1),(8,'2010-01-11 00:00:00','uid2',10),(9,'2010-01-12 00:00:00','uid1',1),(10,'2010-01-13 00:00:00','uid4',1),(11,'2010-01-09 21:00:00','uid1',1),(12,'2010-01-09 21:30:00','uid1',2),(13,'2010-01-10 05:00:00','uid2',3),(14,'2010-01-10 12:00:00','uid1',1),(15,'2010-01-10 12:00:00','uid3',1),(16,'2010-01-10 21:00:01','uid1',7),(17,'2010-01-11 01:00:00','uid2',14),(18,'2010-01-11 05:00:00','uid2',11),(19,'2010-01-11 17:59:00','uid4',13),(20,'2010-01-11 06:00:00','uid5',12),(21,'2010-01-11 18:01:00','uid1',14),(22,'2010-01-12 23:05:00','uid4',17),(23,'2010-01-13 12:01:23','uid6',13);

Answer 1

您可以将表连接到自身，以搜索超过一天的同一用户的条目。当没有一天的匹配时，左连接表中的字段将为NULL。

例如：

select     
  YEAR(cur.ts) as year
, MONTH(cur.ts) as month
, DAY(cur.ts) as day
, case when old.uuid is null then 1 else 0 end as IsNewUser
, count(distinct cur.uuid) as Users
from       table2 cur
left join  table2 old
on         cur.uuid = old.uuid
           and old.ip <> 2
           and old.id > 10
           and cur.ts - old.ts > 1
where      cur.ip <> 2
           and cur.id > 10
group by   year, month, day, IsNewUser
order by   year, month, day, IsNewUser

Answer 2

我对MySQL并不熟悉，但这就是我在Oracle中的表现：

SELECT uuid, 'NEW' as user_type FROM
  (SELECT uuid, MAX(ts) as MAX_TS, MIN(ts) as MIN_TS
     FROM TABLE2
     WHERE ID > 10 AND
           IP <> 2
     GROUP BY uuid
     HAVING MAX_TS > SYSTIMESTAMP - INTERVAL '1' DAY AND
            MAX_TS = MIN_TS) nu
UNION ALL
  SELECT DISTINCT uuid, 'REGULAR' as user_type FROM
    (SELECT uuid, MAX(ts) as MAX_TS
       FROM TABLE2
       WHERE ID > 10 AND
             IP <> 2
       GROUP BY uuid) n
     INNER JOIN (SELECT *
                   FROM TABLE2
                   WHERE ID > 10 AND
                          IP <> 2) t
       ON (t.uuid = n.uuid)
     WHERE n.MAX_TS > SYSTIMESTAMP - INTERVAL '1' DAY AND
           t.ts < SYSTIMESTAMP - INTERVAL '1' DAY AND
           t.ts > SYSTIMESTAMP - INTERVAL '3' DAY;

我在这里看不到TABLE1的用法。你需要使用它吗？

不知道MySQL是否支持SYSTIMESTAMP或INTERVAL构造。但是，希望这会为您提供一些想法。

从24小时前存在的表中查找用户

表2

表1

新用户在18:00

MySQL表转储

2 个答案: