我真的试图渲染一个checkboxlist,从来没有尝试过它,所以我遇到了问题,我试图渲染所有的复选框foreach列或属性,这是动作控制器:
public function actionCreate()
{
$model=new Parametro;
$variable = file_get_contents('protected\column.txt');
$vars = explode(' ', $variable);
// Uncomment the following line if AJAX validation is needed
// $this->performAjaxValidation($model);
if(isset($_POST['Parametro']))
{
$model->attributes=$_POST['Parametro'];
if($model->save())
$this->redirect(array('view','id'=>$model->id));
}
$this->render('create',array(
'model'=>$model,
'variable'=>$vars,
));
}
这是另一些方法的模型
public function rules()
{
// NOTE: you should only define rules for those attributes that
// will receive user inputs.
$variable = file_get_contents('protected\column.txt');
return array(
array('parametro_id', 'required'),
array('parametro_id', 'numerical', 'integerOnly'=>true),
// The following rule is used by search().
// @todo Please remove those attributes that should not be searched.
array('id, parametro_id', 'safe', 'on'=>'search'),
array($variable, 'safe', 'on'=>'search'),
);
}
public function generateAttributeLabel($variable = null)
{
if($variable)
{
$variable = file_get_contents('protected\column.txt');
}
return $variable;
}
public function attributeLabels()
{
return array(
'id' => 'ID',
'parametro_id' => 'Parametro',
);
}
我试图制作复选框列表的表格
<div>
<?php echo $form->checkboxList($model, $variable, array(0 => 1)); ?>
</div>
如果你问,请输入和文件内容
lololo trying
是自动生成的一些列,并且我将它们的名称存储在由空格分隔的此文件上,一切似乎都很好,直到我到达表单上的checkboxlist,它给出了错误,如strpos()或其他东西,如何我可以使这个复选框呈现并将1个数据保存到由特定列检查的那些人吗?
答案 0 :(得分:1)
如果问题是你无法获得复选框,那么试试这个 的 强>
在 _form.php
<div>
<?php echo CHtml::checkBoxList('createCheck', array(), $variable); ?>
</div>
您需要更改控制器操作,以便
public function actionCreate()
{
$model=new Parametro;
$variable = file_get_contents('protected\column.txt');
$vars = explode(' ', $variable);
// make SURE that you are getting $vars as array
if(isset($_POST['Parametro']))
{
$model->attributes=$_POST['Parametro'];
if(isset($_POST['createCheck']))
{
$newVar=array();
$checkVariables=$_POST['createCheck'];
foreach($checkVariables as $key)
{
$newVar[]=$vars[$key];
}
if(!empty($newVar))
{
foreach($newVar as $saveIt)
{
$model->$saveIt='y';
}
$model->save();
}
}
$this->redirect(array('view','id'=>$model->id));
}
$this->render('create',array(
'model'=>$model,
'variable'=>$vars,
));
}
注意: - 它可能会给你一些错误,因为我不知道你的表结构。如果您遇到任何问题,请尝试解决或只是询问