LWJGL：如何判断鼠标是否处于复杂形状的边界？

Question

我的自定义OpenGL显示器上有一个复杂的椭圆形，需要在鼠标进入其边界时修改它的状态（正射透视图永远不会改变，因为这是2D游戏）。我的椭圆是使用：

创建的

public class RenderOval {
public static double r = 0.2;
public static double g = 0.3;
public static double b = 0.5;
public static void renderOval(double locX, double locY, double width, double height){
    GL11.glPushMatrix();

    //Set Drawing Color - Will Remain this color until otherwise specified
    GL11.glColor3d(r,g,b);  

    //Draw Circle
    GL11.glBegin(GL11.GL_POLYGON);
        //Change the 6 to 12 to increase the steps (number of drawn points) for a smoother circle
        //Note that anything above 24 will have little affect on the circles appearance
        //Play with the numbers till you find the result you are looking for
        //Value 1.5 - Draws Triangle
        //Value 2 - Draws Square
        //Value 3 - Draws Hexagon
        //Value 4 - Draws Octagon
        //Value 5 - Draws Decagon
        //Notice the correlation between the value and the number of sides
        //The number of sides is always twice the value given this range
        for(double i = 0; i < 2 * Math.PI; i += Math.PI / 24) //<-- Change this Value
                GL11.glVertex3d(Math.cos(i) * width+locX, Math.sin(i) * height+locY, 0.0);

    GL11.glEnd();
    //Draw Circle
    GL11.glPopMatrix();
}
}

这是一个非常复杂的形状，有许多顶点。但对于常规方块，我会知道如何检查鼠标是否在盒子的边界：

if((Mouse.getX<(box.startX+box.width))&&((Mouse.getX>(box.startX)))){
mouse.isInXBounds = true;
}

然而，我完全失去了如何针对任何自定义形状进行检查。任何帮助将非常感激。谢谢。