Question

你好我正在尝试实现一个服务器和客户端，可以传输任何类型和任何大小的文件，但有一个问题我以某种方式破坏文件。我尝试了很多方法，但无法弄明白。基本上我可以连接，我可以理解客户想要的文件，并可以通过套接字发送。当我尝试打开该文件时，它显示一条错误消息（尝试过winrar，mp4，avi文件）这是我的代码：

//服务器

private void Receive(string receivedFileName, string fileSize)
{
    try
    {
        int receivedBytesLen = 0;
        byte[] incomingFile = new byte[int.Parse(fileSize)];
        activity.AppendText("Preparing to download... \n");
        while (incomingFile != null && int.Parse(fileSize) > receivedBytesLen)
        {
            tempSocket.Receive(incomingFile);

            receivedBytesLen = incomingFile.Length;
            int fileNameLen = BitConverter.ToInt32(incomingFile, 0);
            File.WriteAllBytes(fileDir + "//" + receivedFileName, incomingFile);
        }
        activity.AppendText("File saved to " + fileDir + "\n");
    }
    catch (Exception ex)
    {
        MessageBox.Show(ex.Message);
    }
}

/////////////////////////////////////////////// ///////////////////////

//服务器选项2

private void Receive(string receivedFileName, string fileSize)
{

try
{

    byte[] incomingFile = new byte[10124 * 5000];
    activity.AppendText("Preparing to download... \n");
    BinaryWriter bWrite = new BinaryWriter(File.Open(folderBrowserDialog1.SelectedPath + "//" + receivedFileName, FileMode.Append));
    int receivedBytesLen = tempSocket.Receive(incomingFile, incomingFile.Length, 0);
    int fileNameLen = BitConverter.ToInt32(incomingFile, 0);
    //string fileName = Encoding.UTF8.GetString(incomingFile, 4, fileNameLen);

    //bWrite.Write(incomingFile, 4 + fileNameLen, receivedBytesLen - 4 - fileNameLen);
    while (receivedBytesLen > 0)
    {
        receivedBytesLen = tempSocket.Receive(incomingFile, incomingFile.Length, 0);
        if (receivedBytesLen == 0)
        {
            bWrite.Close();
        }
        else
        {
            bWrite.Write(incomingFile, 0, receivedBytesLen);
        }
    }
    activity.AppendText("File saved to " + fileDir + "\n");
}
catch (Exception ex)
{
    MessageBox.Show(ex.Message);
}

}

/////////////////////////////////////////////// //////////////////////

//客户端

                private void Upload_Click(object sender, EventArgs e)
    {//Uploads selected file after clicking upload button.
        try
        {
            if (clientSocket.Connected)
            {
                byte[] buffer = new byte[1024];
                byte[] sendingFile = null;
                sendingFile = File.ReadAllBytes(openFileDialog1.FileName);
                FileInfo f = new FileInfo(openFileDialog1.FileName);
                string fileSize = f.Length.ToString();
                buffer = Encoding.Default.GetBytes(getUserName.Text + "Upload" + openFileDialog1.SafeFileName + "size" + fileSize + "end");
                clientSocket.Send(buffer);
                activityLog.AppendText("Sending File \n");
                int bytesToBeSent = sendingFile.Length;
                int bytesActuallySent = 0;
                while(bytesActuallySent < bytesToBeSent){
                bytesActuallySent += clientSocket.Send(sendingFile, bytesActuallySent, bytesToBeSent -bytesActuallySent, 0);
                }
                    activityLog.AppendText("File Sent.\n");
            }
        }
        catch(Exception ex){
            MessageBox.Show(ex.Message);
        }

    }

Answer 1

为了满足任何大小的文件，你需要一个选项＃3，一个读取字节块直到接收到所有字节的选项，你的选项＃1在2 GIG盒子上运行的3 GIG文件上不会那么好......

这是一个链接：http://www.yoda.arachsys.com/csharp/readbinary.html

我喜欢此链接中的选项＃2。

然而，在他们写入memoryStream的示例中，您应该写入文件流，即目标文件。

Answer 2

服务器选项＃2更好。但是有一些改进

套接字接收缓冲区受OS决定，一般为8192
在客户端和服务器中使用FileStream，不要忘记在文件下载后关闭文件流

客户端：

FileStream fileStream = new FileStream(filePath, FileMode.Open)
byte[] buff = new byte[8192];
do
{
    bytesRead = fileStream.Read(buff, 0, buff.Length);              
    sock.send(dataSock, buff, bytesRead);
}while (bytesRead > 0);
fileStream.close();

服务器：

FileStream fileStream = new FileStream(filePath, FileMode.Open)
do
{
    bytesRead = sock.receive(buff, 0, buff.Lenght);
    fileStream.Write(buff, 0, bytesRead );
}while (bytesRead > 0);
fileStream.close();

通过套接字传输文件（bir和小尺寸）

2 个答案: