Question

您好我正在尝试通过以下链接连接网络服务的Android应用程序

http://jatin4rise.wordpress.com/2010/10/03/part-2-calling-a-webservice-from-android-application/#comment-125

我可以在Web服务中创建xsdl文件这是android

中的代码

package com.example.androidwsdlfrontend;

import org.ksoap2.SoapEnvelope;
import org.ksoap2.serialization.SoapObject;
import org.ksoap2.serialization.SoapSerializationEnvelope;
import org.ksoap2.transport.HttpTransportSE;
import android.app.Activity;
import android.os.Bundle;
import android.widget.TextView;

public class AndroidWSDLFrontEnd extends Activity {
    private String METHOD_NAME = "sum"; // our webservice method name
    private String NAMESPACE = "http://calculator.backend.web.org";//&#8221"; // Here package name in webservice with reverse order.;

    private String SOAP_ACTION = NAMESPACE + METHOD_NAME; // NAMESPACE + method name

    private static final String URL = "http://10.0.2.2:8080/AndroidBackend/services/Calculate?wsdl";//&#8221"; // you

    /** Called when the activity is first created. */
    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_android_wsdlfront_end);

        TextView tv = (TextView) findViewById(R.id.txtAddition);
        try {
            SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME);
            request.addProperty("i", 5);
            request.addProperty("j", 15);
            SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11);
            envelope.dotNet = true;
            envelope.setOutputSoapObject(request);
            HttpTransportSE androidHttpTransport = new HttpTransportSE(URL);
            androidHttpTransport.call(SOAP_ACTION, envelope);
            Object result = envelope.getResponse();
            System.out.println("Result: " + result.toString());
            ((TextView) findViewById(R.id.txtAddition)).setText("Addition: "+ result.toString());
        } catch (Exception E) {
            E.printStackTrace();
            ((TextView) findViewById(R.id.txtAddition)).setText("Error: "+ E.getClass().getName() + ":" + E.getMessage());
        }
    }
}

在我编译时的上述代码中，我收到错误

SoapObject request = new SoapObject（NAMESPACE，METHOD_NAME）;

但我不知道如何解决它。请帮我。我在那个特定位置提到了我的ipaddress。

Answer 1

以下视频教程可能有所帮助： https://www.youtube.com/watch?v=v9EowBVgwSo https://www.youtube.com/watch?v=t8__EuSS69E
不要忘记添加访问互联网的权限
检查参数情况是否与中的相同网络服务
检查您是否已将库路径添加到buil.gradle

Android应用程序与Web服务的连接

1 个答案: