我想创建分面搜索。 我有一些MySQL表:
**products_table**
id name category_set
9 Female.Jeans 157
10 Male.Jeans 157
**fields_table**
id name
1 Color
2 Gender
**fields_values_table**
id fieldsid value
1 1 White
2 1 Black
3 1 Orange
4 1 Green
5 1 Blue
6 2 Male
7 2 Female
**products_to_fields_values**
productid fields_values_id
9 5
9 7
10 5
10 6
我有php功能来搜索我的产品:
private function get_products ($filter) {
$per_page = (isset($filter["show_by"]) && $filter["show_by"] >= 25 && $filter["show_by"] <= 100) ? intval($filter["show_by"]) : 25;
$start = (isset($filter["page_id"]) && intval($filter["page_id"])) ? ($filter["page_id"] -1)*$per_page : 0;
$data = [];
$search_vids = false;
if (isset($filter['vid']) && is_array($filter['vid'])) {
$in_set = implode(',', array_filter($filter['vid']));
if (strlen($in_set)) {
$search_vids = true;
}
}
if ($search_vids) {
$sql_counter = 'SELECT COUNT(*) count FROM `products` WHERE 1=1';
$sql_result = 'SELECT
P.id,
P.name,
P.status
FROM `products` P, `products_to_fields_values` V WHERE 1=1';
} else {
$sql_counter = 'SELECT COUNT(*) count FROM `products` WHERE 1=1';
$sql_result = 'SELECT
`id`,
`name`,
`status`
FROM `products` WHERE 1=1';
}
if ($search_vids) {
$sql_counter .= ' AND P.id = V.productid AND V.fields_values_id IN ('.$in_set.')';
$sql_result .= ' AND P.id = V.productid AND V.fields_values_id IN ('.$in_set.')';
}
if (isset($filter['cid']) && intval($filter['cid'])) {
$sql_counter .= ' AND FIND_IN_SET(:cid, `category_set`)';
$sql_result .= ' AND FIND_IN_SET(:cid, `category_set`)';
$data[':cid'] = $filter['cid'];
}
if (isset($filter['price']['from']) && floatval($filter['price']['from'])) {
$sql_counter .= ' AND `price` >= :price_from END ';
$sql_result .= ' AND `price` >= :price_from END ';
$data[':price_from'] = $filter['price']['from'];
}
if (isset($filter['price']['to']) && floatval($filter['price']['to'])) {
$sql_counter .= ' AND `price` <= :price_to ';
$sql_result .= ' AND `price` <= :price_to ';
$data[':price_to'] = $filter['price']['to'];
}
if (isset($filter['q']) && strlen($filter['q']) > 0) {
$search = filter_var($filter['q'], FILTER_SANITIZE_STRING);
$sql_counter .= ' AND (`name` LIKE concat("%", :search_name, "%")';
$sql_result .= ' AND (`name` LIKE concat("%", :search_name, "%")';
$sql_counter .= ' OR `product_tag` LIKE concat("%", :search_tag, "%"))';
$sql_result .= ' OR `product_tag` LIKE concat("%", :search_tag, "%"))';
$data[':search_name'] = $search;
$data[':search_tag'] = $search;
}
$count = $this->db1->query($sql_counter)->single($data)['count'];
if ($search_vids) {
$sql_result .= ' GROUP BY P.id LIMIT :start, :perpage';
} else {
$sql_result .= ' LIMIT :start, :perpage';
}
$data[':start'] = $start;
$data[':perpage'] = $per_page;
$rows = $this->db1->query($sql_result)->resultset($data);
$pages = ($count >0) ? ceil($count/$per_page) : 0;
$product_list = array();
$fields = array();
$breadcrumbs = array();
$cid = 0;
if(count($rows)>0) {
foreach ($rows as $row) {
$product_list[] = $row;
}
}
$categories = new categories($this->app, $this->user);
$categories_arr = $categories->load();
if (isset($filter['cid']) && intval($filter['cid'])) { // Categories page
$sql = 'SELECT GROUP_CONCAT(fieldid) AS fields_set FROM `fields_to_categories` WHERE `category_set`= :cid';
$fields_ids = $this->db1->query($sql)->bind(':cid', $filter['cid'])->single();
if (isset($fields_ids['fields_set']) && !empty($fields_ids['fields_set'])) {
$fields = new fields($this->app, $this->user);
$fields = $fields->load_controller($fields_ids['fields_set'], false); // False = fields with status = 1
}
$breadcrumbs= $categories->getBreadcrumbs($filter['cid']);
} else {
$breadcrumbs= $categories->getBreadcrumbs($cid);
}
return array(
'products' => $product_list,
'categories' => $categories_arr["categories"],
'filter' => isset($filter['cid']) && intval($filter['cid']) && isset($fields['fields']) ? $fields['fields'] : '',
'breadcrumbs' => isset($breadcrumbs['path']) ? $breadcrumbs['path'] :'',
'total' => $count,
'pages' => intval($pages),
'status' => 1
);
}
这会给我一张照片: 但问题出在这里:
当我检查男性(1个产品)时,蓝色应为1.请检查下图。 如何修复我的搜索功能?
答案 0 :(得分:1)
您的查询问题是,如果产品与单个过滤器匹配,它将返回产品。
由于您需要匹配所有过滤器,因此您需要对查询进行一些更改
这可以通过2种方式实现
计算每个产品匹配的过滤器数量,只有在匹配特定数量的过滤器时才会返回。使用小提琴的示例查询
select
pfv.productid, pt.name
from
fields_table ft
inner join
fields_values_table fvt
on
(ft.id=fvt.fieldsid)
inner join
products_to_fields_values pfv
on
(pfv.fields_values_id=fvt.id)
inner join
products_table pt
on
(pt.id=pfv.productid)
inner join
product p
on
(p.productid=pt.id) <-- Assuming product table having price and 1-1 mapping
where
p.price > 500 and p.categoryid=102 and
(ft.name='color' and fvt.value='Blue')or
(ft.name='gender' and fvt.value='female')
group by
pfv.productid, pt.name
having count(*)>=2 <--Maintain the count of how many field value filters it should match. In this example we have only 2 filters
| PRODUCTID | NAME |
|-----------|--------------|
| 9 | Female.Jeans |