Question

如何在PHP中传递多个隐藏输入的当前行的一个值。我有以下代码：

foreach($portfolio as $portfolio){
echo  "<tr class ='table-comments'>";
echo  "<td>".$portfolio['portfolio_title']."</td>";
echo  "<td class = 'comment-content'>".$portfolio['portfolio_client']."</td>";
echo  "<td><a target = '_blank' href = ".$portfolio['portfolio_link'].">".$portfolio['portfolio_link']."</a></td>";
echo  "<td>";
echo  "<input type='hidden' name='portfolio_id' value='" . $portfolio['portfolio_id'] . "' />";
echo "<input type = 'submit'  value = 'Edit'>";
echo "<input type = 'submit' value = 'Move to Trash' class = 'action-button'>";
echo  "</td>";
echo  "</tr>";
}

我也有触发表单的每一行的提交按钮。当我单击提交按钮时，它会提交隐藏输入行的所有值。我只想要点击的按钮行值。

网址如下：

/portfolio?portfolio_id=1&portfolio_id=2&portfolio_id=3&portfolio_id=4依此类推

我只想要

/portfolio?portfolio_id=3

Answer 1

每行都有一个新表格......

<form method="get">

</form>

像这样：

foreach($portfolio as $portfolio){

    echo  "<tr class ='table-comments'>";
    echo  "<td>".$portfolio['portfolio_title']."</td>";
    echo  "<td class = 'comment-content'>".$portfolio['portfolio_client']."</td>";
    echo  "<td><a target = '_blank' href = ".$portfolio['portfolio_link'].">".$portfolio['portfolio_link']."</a></td>";
    echo  "<td>";
    echo '<form method="get">';
    echo  "<input type='hidden' name='portfolio_id' value='" . $portfolio['portfolio_id'] . "' />";
    echo "<input type = 'submit'  value = 'Edit'>";
    echo "<input type = 'submit' value = 'Move to Trash' class = 'action-button'>";
    echo "</form>";
    echo  "</td>";
    echo  "</tr>";

}

Answer 2

表单标记应包含在循环中。

更改此

foreach ($portfolio as $portfolio) {
    echo  "<tr class ='table-comments'>";
    echo  "<td>".$portfolio['portfolio_title']."</td>";
    echo  "<td class = 'comment-content'>".$portfolio['portfolio_client']."</td>";
    echo  "<td><a target = '_blank' href = ".$portfolio['portfolio_link'].">".$portfolio['portfolio_link']."</a></td>";
    echo  "<td>";
    echo  "<input type='hidden' name='portfolio_id' value='" . $portfolio['portfolio_id'] . "' />";
    echo "<input type = 'submit'  value = 'Edit'>";
    echo "<input type = 'submit' value = 'Move to Trash' class = 'action-button'>";
    echo  "</td>";
    echo  "</tr>";
}

为：

foreach ($portfolio as $portfolio) {
    echo  "<tr class ='table-comments'>";
    echo  "<td>".$portfolio['portfolio_title']."</td>";
    echo  "<td class = 'comment-content'>".$portfolio['portfolio_client']."</td>";
    echo  "<td><a target = '_blank' href = ".$portfolio['portfolio_link'].">".$portfolio['portfolio_link']."</a></td>";
    echo  "<td>";
    echo  "<form action='process.php' method='get'>";
    echo  "<input type='hidden' name='portfolio_id' value='" . $portfolio['portfolio_id'] . "' />";
    echo "<input type = 'submit'  value = 'Edit'>";
    echo "<input type = 'submit' value = 'Move to Trash' class = 'action-button'>";
    echo "</form>";
    echo  "</td>";
    echo  "</tr>";
}

Answer 3

如果您提交的内容都是该ID，并且您使用的是GET而不是POST，那么您甚至可以不使用表单而是使用链接。如果需要，您仍然可以将链接设置为看起来像按钮，但使用链接会在语义上更有意义。删除隐藏的输入，并让每个链接都有您想要的URL。

单击当前行中提交的隐藏输入的一个值

3 个答案: