Question

以下是我正在尝试制作的节目的摘录。我希望得到它，当有人输入短语“是”或“否”时，它会在if语句中得到响应。注意它们现在是占位符，我打算用这些语句做更多的事情。

请注意代码不完整，因此可能没有完全合理，但我的问题仍然存在。

主要课程：

package adventure;

import java.util.Scanner;

public class Main {
    int boots, leggings, chestplate, helm;
    static int hp = 25;
    int dogde;
    int dagger = 1;
    int ssword = 0;
    int lsword = 0;
    int shield = 0;
    static int strength = 1;
    static int agility = 1;
    static int health = 25;
    int stats, inventory;
    static int gold = 10;
    static int x = 0;
    int senemy = 0, menemy = 0, lenemy = 0, boss = 0;
    public static void main (String[]args)  {

        System.out.println("Welcome to the adventure game! Enter 0 to start"); 
        Scanner sc = new Scanner(System.in);
        int menu = sc.nextInt();
            if (menu == 0)  {
                System.out.println("Welcome to the menu! It can be reopened anytime by entering 0");
                System.out.println("Enter:");
                System.out.println("1 to view player stats");
                System.out.println("2 to view your inventory");
                System.out.println("3 to view your gold amount");
                System.out.println("4 to continue your adventure");
        while (x == 0)
            switch (sc.nextInt())   {
            case 1:
                System.out.println("You have " + hp + " out of " + health + " hp, " + agility + " agility and " + strength + " strength");
                break;
            case 2:
                System.out.println("You have ");
                break;
            case 3:
                System.out.println("You have " + gold + " gold");
                break;
            case 4:
                System.out.println("Let the adventure begin..."); x=2;
                break;
            default:
                System.out.println("Menu exited"); x=1;
                break;
            }
        }
            if (x == 2){
                Level1 level1Object = new Level1();

            }
    }
}

我特别关注案例2。

package adventure;
import java.util.Scanner;

public class Level1 {
String yes = "Yes";
String no = "No";
{   Scanner sc = new Scanner(System.in);
    int x = 2;
    System.out.println("Level 1 out of 12");
    System.out.println("You wake up in a town called Haven");
    System.out.println("Enter:");
    System.out.println("1 = Visit the armory, 2 = Find a quest, 3 = Proceed to the next level");
    while (x == 2){
    switch (sc.nextInt()){ 
    case 1:
        System.out.println("You enter the armory"); //placeholder
        break;
    case 2:
        System.out.println("You ask the local guard captain for a quest");
        System.out.println("Captain: Orcs have taken the south watchtower, take it back and I will reward you 10 gold");
        System.out.println("Accept quest? Enter: Yes or No");
        String input = sc.nextLine();
        System.out.println(input);
        if (input.equals("Yes"))    {
            System.out.println("Quest accepted"); //placeholder
        }
        else if (input.equals("No"))    {
            System.out.println("Quest denied"); //placeholder
        }
        break; //placeholder
    case 3:
        System.out.println("You proceed to the next level"); //placeholder
        break;
    default:
        System.out.println("Invalid response");
        System.out.println(0); //test, delete
        break;
        }
    }
    }
}

错误：

Exception in thread "main" java.util.InputMismatchException
    at java.util.Scanner.throwFor(Scanner.java:840)
    at java.util.Scanner.next(Scanner.java:1461)
    at java.util.Scanner.nextInt(Scanner.java:2091)
    at java.util.Scanner.nextInt(Scanner.java:2050)
    at adventure.Level1.<init>(Level1.java:14)
    at adventure.Main.main(Main.java:52)

编辑我通过将“否”线更改为“是”并使用了另一个扫描仪而不是“sc”来修复它。

Answer 1

import java.io.FileNotFoundException;
import java.util.HashMap;
import java.util.Map;

import java.util.Scanner;

public class Level1 {
 private static String YES = "Yes";
 private static String NO = "No";

 public Level1(){
Scanner sc = new Scanner(System.in);
    int x = 2;
    System.out.println("Level 1 out of 12");
    System.out.println("You wake up in a town called Haven");
    System.out.println("Enter:");
    System.out.println("1 = Visit the armory, 2 = Find a quest, 3 = Proceed to the next level");
    while (x == 2){
     switch (sc.nextInt()){ 
      case 1:
       System.out.println("You enter the armory"); //placeholder
       break;
      case 2:
       System.out.println("You ask the local guard captain for a quest");
       System.out.println("Captain: Orcs have taken the south watchtower, take it back and I will reward you 10 gold");
       System.out.println("Accept quest? Enter: Yes or No");
       String input = sc.nextLine();
       System.out.println(input);
       if (input.equalsIgnoreCase(YES))    {
        System.out.println("Quest accepted"); //placeholder
       }
       else if (input.equalsIgnoreCase(NO))    {
        System.out.println("Quest denied"); //placeholder
       }
       break; //placeholder
      case 3:
       System.out.println("You proceed to the next level"); //placeholder
       break;
      default:
       System.out.println("Invalid response");
       System.out.println(0); //test, delete
       break;
     }
   }    
  }
}

Answer 2

您正在使用sc.nextInt()阅读输入。这会阻碍“是”或“否”等输入。相反，您应该简单地将下一行读作字符串。然后，您可以测试它是“是”还是“否”，如果不是，则可以尝试将其解析为int。

如何检查字符串的扫描程序是否相等并在java中使用它？

2 个答案: