Question

我有一张包含很多复选框的表格。复选框通过循环生成，并被赋予唯一的ID。

$get_depts = mysql_query("select dept_id, dept_name from depts where bus_id = '{$business['bus_id']}'");
while(($department = mysql_fetch_assoc($get_depts)))
{
    echo '<tr><td>'.$department['dept_name'].'</td>';
    $req_fields = mysql_fetch_assoc(mysql_query("SELECT employees, department, customer, salespeople, acct_nbrs, categories, subcategories, case_ids, login_ids, phone, phext, cust_email, problem, resolution, source, priority FROM required_fields WHERE dept_id = '{$department['dept_id']}'"));
    if($req_fields['employees'] == 'YES'){echo '<td><input type="checkbox" id="employees[]" name="employees[]" value="YES" checked></td>';}
    else echo'<td><input type="checkbox" id="employees[]" name="employees[]" value="YES"></td>';
}

正如您所看到的，复选框的id和名称的一个例子是employees1，employees2等。

提交后，我尝试循环回到我的部门，再次获取唯一的ID号码。然后我尝试更新我的桌子。

$get_depts = mysql_query("select dept_id, dept_name from depts where bus_id = '{$business['bus_id']}'");
while(($department = mysql_fetch_assoc($get_depts)))
{
    mysql_query("Update required_fields set employees = '{$_POST['employees'.$department['dept_id']]}' where dept_id = '{$department['dept_id']");
}

我显然没有使用post变量的正确语法。我怎样才能正确使用$ _POST ['employees'] + $ department ['dept_id']？

修改的

FINAL 结果如下所示。例如，如果$ department ['dept_id'] = 10，那么post变量的名称将是$ _POST ['employees10']

Answer 1

如果您对将它们直接连接起来感到满意，可以使用：

$_POST['employees'] . $department['dept_id']

.用于PHP中的连接。

例如：

$get_depts = mysql_query("select dept_id, dept_name from depts where bus_id = '{$business['bus_id']}'");
while(($department = mysql_fetch_assoc($get_depts)))
{
 //
 // I prefer to do my concat outside of the query!
 //
 $employees = $_POST['employees'] . $department['dept_id'];

 //I assume this query isn't really what you're running.  Pseudo-code, no?
    mysql_query("Update required_fields set employees = '$employees' where dept_id = '{$department['dept_id']}");
}

Answer 2

在第一个代码中，您需要为输入字段指定uniqe名称。您正在使用数组，但它只会保存一些自动生成的数字（0,1,2,3,4 ...）您应该将其更改为数据库中的部门ID，因此它看起来更像是这样：

$depid=$department['dept_id'];
if($req_fields['employees'] == 'YES'){echo "<input type='checkbox' id='employees[{$depid}]' name='employees[{$depid}]' value='YES' checked></td>";}
else echo "<td><input type='checkbox' id='employees[]' name='employees[]' value='YES'></td>";
}

您还需要使用双引号而不是单引号，因为只有这样您的字符串才会被变量解析。

然后在你的第二个代码中，Post部分看起来像这样：

$dep = $_POST['employees'][$department['dept_id'];
mysql_query("Update required_fields set employees = '$dep' where dept_id = '{$department['dept_id']");

如何在查询字符串中的post变量中包含变量？ -php

2 个答案: