“字段列表”中的未知列

时间:2013-12-26 18:24:58

标签: php sql

我在尝试更新/插入记录时不断收到此错误:

  

'字段列表'中的未知列'test'SQL = INSERT INTO oovea_vehiclemanager_feature_vehicles(fk_vehicleid,fk_featureid,fk_value)VALUES(13,56,test)

以下是我设置的表单:

<?php
if (isset($_POST['feature'])){
    $feature = $_POST['feature'];
    $featureInput = $_POST['featureInput'];
    $database->setQuery("DELETE FROM #__vehiclemanager_feature_vehicles WHERE fk_vehicleid = " . $vehicle->id);
    $database->query();
    for ($i = 0; $i < count($feature); $i++) {
        $database->setQuery("INSERT INTO #__vehiclemanager_feature_vehicles (fk_vehicleid, fk_featureid, fk_value) VALUES (" . $vehicle->id . ", " . $feature[$i] . ", " . $featureInput[$i] . ")");
        $database->query();
    }
}
?>

这是我的表单字段:

<?php 
if($vehicle_feature[$i]->name): ?>
<div class="checkbox_vm">   
    <input type="checkbox" class="checkbox_veh" id="checkbox_addveh<?php echo $i; ?>" <?php if ($vehicle_feature[$i]->check) echo "checked"; ?> name="feature[]" value="<?php echo $vehicle_feature[$i]->id; ?>">   
    <label for="checkbox_addveh<?php echo $i; ?>"><?php echo $vehicle_feature[$i]->name; ?></label>    
    <input type="text" class="" id="input_addveh<?php echo $i; ?>" name="featureInput[]" value="<?php echo $vehicle_feature[$i]->value; ?>">    
</div>
<?php endif; ?>

显然,从上面的错误中,我可以看到featureInput字段的值正在发布,而我的“INSERT INTO”的语法看起来是正确的。此外,如果我只删除“fk_value”,“$ featureInput [$ i]。

的列,它将起作用。

2 个答案:

答案 0 :(得分:1)

尝试使用单引号:

VALUES ('" . $vehicle->id . "', '" . $feature[$i] . "', '" . $featureInput[$i] . "')

答案 1 :(得分:1)

您尚未在查询中正确引用字符串数据。

试试这个:

<?php
if (isset($_POST['feature'])) {
    $feature = $_POST['feature'];
    $featureInput = $_POST['featureInput'];
    $database->setQuery("DELETE FROM #__vehiclemanager_feature_vehicles WHERE fk_vehicleid = $vehicle->id");
    $database->query();
    for ($i = 0; $i < count($feature); $i++) {
        $database->setQuery("INSERT INTO #__vehiclemanager_feature_vehicles (fk_vehicleid, fk_featureid, fk_value) VALUES ($vehicle->id,$feature[$i],'$featureInput[$i]')");
        $database->query();
    }
}
?>

您还需要需要处理一些严重的SQL注入问题,否则攻击者很容易破解您的数据库。