Question

select 
   t.Sno, t.childid,
   (select customername as n from customerprofile c where c.cusid = t.childid) as name,t.earnedmoney as commission,
   (select p.bookingamt from propertyregistration p, customerprofile c where p.applicationno = c.applicationno and c.cusid = t.childid) as bookingamt,
   (select p.totalarea from propertyregistration p, customerprofile c where p.applicationno = c.applicationno and c.cusid = t.childid) as totalarea ,
   (select childid from tbl_level where parentid = t.childid) as child
from 
   tbl_level t 
where 
   parentid = @id

这是

的程序

(select childid from tbl_level where parentid = t.childid) as child

如果有单个记录，则轻易获取

在有多条记录的情况下，它会抛出子查询返回多个值的错误

请帮我检查多条记录

Answer 1

试试这个：

SELECT t.Sno, t.childid, c.customername AS NAME, t.earnedmoney AS commission, 
       p.bookingamt AS bookingamt, p.totalarea AS totalarea, 
       MAX(STUFF(A.childid, 1, 1, '')) AS childs
FROM tbl_level t 
LEFT JOIN customerprofile c ON c.cusid = t.childid
LEFT JOIN propertyregistration p ON p.applicationno = c.applicationno 
CROSS APPLY(SELECT ' ' + t1.childid FROM tbl_level t1 WHERE t1.parentid = t.childid FOR XML PATH('')) AS A (childid)
WHERE parentid = @id 
GROUP BY t.Sno, t.childid, c.customername, t.earnedmoney, p.bookingamt, p.totalarea

从所有子ID中获取客户名称：

SELECT t.Sno, t.childid, c.customername AS NAME, t.earnedmoney AS commission, 
       p.bookingamt AS bookingamt, p.totalarea AS totalarea, 
       MAX(STUFF(A.customerNames, 1, 1, '')) AS childs
FROM tbl_level t 
LEFT JOIN customerprofile c ON c.cusid = t.childid
LEFT JOIN propertyregistration p ON p.applicationno = c.applicationno 
CROSS APPLY(SELECT ',' + c1.customername 
            FROM tbl_level t1 
            INNER JOIN customerprofile c1 ON c1.cusid = t1.childid
            WHERE t1.parentid = t.childid 
            FOR XML PATH('')
           ) AS A (customerNames)
WHERE parentid = @id 
GROUP BY t.Sno, t.childid, c.customername, t.earnedmoney, p.bookingamt, p.totalarea

如何通过存储过程获取多个记录

1 个答案: