Question

我想将一个表（独占）从表中匹配到另一个表，并且只返回与ALL匹配的行。这是我的例子：

DECLARE @T1 TABLE (Gr int, Dim char(1), Val int)
INSERT INTO @T1 VALUES (1,'A',10)
INSERT INTO @T1 VALUES (1,'B',200)
INSERT INTO @T1 VALUES (1,'B',201)
INSERT INTO @T1 VALUES (1,'B',202)
INSERT INTO @T1 VALUES (1,'C',22)
INSERT INTO @T1 VALUES (1,'C',23)
INSERT INTO @T1 VALUES (1,'C',24)

DECLARE @T2 TABLE (eDim char(1), eVal int)
INSERT INTO @T2 VALUES ('B', 200)
INSERT INTO @T2 VALUES ('C', 29)

SELECT T1.Gr, T1.Dim, T1.Val FROM @T1 T1
WHERE EXISTS (SELECT * FROM @T2 T2 WHERE T2.eDim = T1.Dim AND T2.eVal = T1.Val)

在上面的示例中，查询从T1返回对应于B-200值对的一行。我真正需要的是当B和C值都匹配T2时返回两个记录，或者如果一个或多个记录不匹配则不返回任何记录。类似于“WHERE EXISTS ALL”之类的东西，但SQL SERVER无法识别。

Answer 1

一个人去做

SELECT Gr, eDim Dim, eVal Val
  FROM
( 
  SELECT T1.Gr
    FROM @T1 t1 JOIN @T2 t2
      ON t1.dim = t2.edim
     AND t1.val = t2.eval
   GROUP BY t1.gr
  HAVING COUNT(*) = 
  (
    SELECT COUNT(*) FROM @T2
  )
) q CROSS JOIN @T2

以下是 SQLFiddle 演示尝试取消注释上一个INSERT INTO @T1并再次运行查询

或

SELECT gr, dim, val
  FROM
(
  SELECT gr, dim, val, COUNT(*) OVER (PARTITION BY gr) cnt
      FROM @T1 t1 JOIN @T2 t2
        ON t1.dim = t2.edim
       AND t1.val = t2.eval
   GROUP BY gr, dim, val
) q
 WHERE cnt = 
(
  SELECT COUNT(*) FROM @T2
)

以下是 SQLFiddle 演示尝试取消注释上一个INSERT INTO @T1并再次运行查询

将SubQuery中的多行匹配到主查询中

1 个答案: