Question

fiddle

CREATE TABLE STUDY
(
  [ID][INT],
  STUDY_DATE VARCHAR(40),
  START_TIME VARCHAR (40),
  END_TIME VARCHAR (40)

)

INSERT INTO STUDY VALUES(1,'2013-12-26','11:30:00','11:31:00')

SELECT 
    STUDY_DATE,
    START_TIME,
    END_TIME
FROM 
    STUDY
WHERE
    STUDY_DATE>='2013-12-25' 
    AND CONVERT(VARCHAR(8),START_TIME,108)>='18:41:34' 
    AND STUDY_DATE<='2013-12-26'
    AND CONVERT(VARCHAR(8),END_TIME,108)<='12:41:34'

这里当start_time大于结束时间时，它给出零结果。我该怎么办

Answer 1

这不是处理日期和时间的推荐方法，但如果您无法更改数据类型：

SELECT
    STUDY_DATE,
    START_TIME,
    END_TIME
FROM
    STUDY
WHERE
    CAST(STUDY_DATE + ' ' + START_TIME AS DATETIME) >= '2013-12-25 18:41:34' AND
    CAST(STUDY_DATE + ' ' + END_TIME AS DATETIME) <= '2013-12-26 12:41:34'

--- --- ORIG

如果可以，您应该更加尊重适当的数据类型。您的设计还有其他选择 - 可能是：

CREATE TABLE STUDY
(
ID INT, -- Consider PRIMARY KEY IDENTITY(1,1)?
START_TIME DATETIME,
END_TIME DATETIME
);

这样你可以更恰当地使用日期/时间：

SELECT * FROM STUDY WHERE START_TIME >= '12/25/2013 18:41:34' AND END_TIME <= '12/26/2013 12:41:34'

Answer 2

我猜你试图将开始时间与你的日期和第二次约会的结束时间分组。

如果是这样，你可以这样做：

SELECT STUDY_DATE,START_TIME,END_TIME
FROM STUDY
WHERE
STUDY_DATE BETWEEN  '2013-12-25' AND '2013-12-26'
AND 
(
  (STUDY_DATE = '2013-12-25' AND CONVERT(VARCHAR(8),START_TIME,108)>='18:41:34')
  OR
  (STUDY_DATE = '2013-12-26' AND CONVERT(VARCHAR(8),END_TIME,108)<='12:41:34')
)

以下是fiddle

根据日期和时间varchar数据类型进行搜索

2 个答案: