在awk中打​​印字符串值会导致错误

Question

fatal: not enough arguments to satisfy format string
    `%s SPT=80'
     ^ ran out for this one

这是我的代码

for ((h = 1 ; h < 4 ; h++ )); do 
    x=$(awk -v i=h -v j=17 'FNR == 2 {printf "%s " $j}' newiptables.log)
        echo $x

这是我的档案

Dec 26 09:17:51 localhost kernel: IN=eth0 OUT= MAC=00:10:c6:a8:da:68:00:90:7f:9c:50:5a:08:00 SRC=198.252.206.16 DST=10.128.1.225 LEN=313 TOS=0x00 PREC=0x00 TTL=64 ID=59334 PROTO=TCP SPT=80 DPT=56506 WINDOW=46535 RES=0x00 ACK PSH URGP=0 
Dec 26 09:17:52 localhost kernel: IN=eth0 OUT= MAC=00:10:c6:a8:da:68:00:90:7f:9c:50:5a:08:00 SRC=198.252.206.16 DST=10.128.1.225 LEN=1440 TOS=0x00 PREC=0x00 TTL=64 ID=47303 PROTO=TCP SPT=80 DPT=56506 WINDOW=46535 RES=0x00 ACK URGP=0 
Dec 26 09:17:52 localhost kernel: IN=eth0 OUT= MAC=00:10:c6:a8:da:68:00:90:7f:9c:50:5a:08:00 SRC=198.252.206.16 DST=10.128.1.225 LEN=1440 TOS=0x00 PREC=0x00 TTL=64 ID=47559 PROTO=TCP SPT=80 DPT=56506 WINDOW=46535 RES=0x00 ACK URGP=0 

Answer 1

问题是printf的{​​{1}}命令中缺少逗号：

awk

引用manual：

  

一个简单的awk -v i=h -v j=17 'FNR == 2 {printf "%s ", $j}' newiptables.log ^ |== This is needed 语句如下所示：

printf