从2选择语句输出不同的列

Question

我希望实现类似的目标;

例如

ID  VALUE NAME
1   1234  COUNTER
2   1235  BAGGAGE

输出：

COUNTER BAGGAGE
1234    1235

脚本：

SELECT ID, VALUE, NAME FROM table WHERE ID = 1
UNION ALL
SELECT ID, VALUE, NAME FROM table WHERE ID = 2

结果：

ID  VALUE NAME
1   1234  COUNTER
2   1235  BAGGAGE

这是一个行到列的方法吗？

Answer 1

试试这个::

select id,case when name='counter' then value else ' ' end as counter,

        case when name='baggage' then value else ' ' end as baggage

        from table

输出

  id  counter baggage
   1   1234
   2           1235

fiddle demo

Answer 2

在这种情况下，您使用以下查询。它不是非常通用，但在特定情况下可能就足够了，因为它简单易用。

select 
(select top 1 value from yourtable where name = 'counter') as counter,
(select top 1 value from yourtable where name = 'baggage') as baggage

SQL Fiddle demo

Answer 3

您可以像这样使用PIVOT：

DECLARE @DataSource TABLE
(
   [ID] TINYINT
  ,[VALUE] SMALLINT
  ,[Name] VARCHAR(12)
)

INSERT INTO @DataSource ([ID],[VALUE],[Name])
VALUES (1,1234,'COUNTER')
      ,(2,1235,'BAGGAGE')     

SELECT  [COUNTER]
       ,[BAGGAGE]
FROM 
(
    SELECT [VALUE]
          ,[Name]
    FROM @DataSource 
) AS DS
PIVOT
(
  MAX([VALUE]) FOR [Name] IN ([COUNTER], [BAGGAGE])
) AS PVT

输出：

检查example。

Answer 4

另一个标准解决方案

select max(case when name='counter' then value end) as counter,

       max(case when name='baggage' then value end) as baggage

from table