Question

这是我创建的用于使用户遵循模型的类。但是，它似乎不正常。当我在管理员中创建一个关注者时，它会一直打开一个新的添加UserFollwing窗口来填充“关注”字段。所以，我无法创建它。

class UserFollowing(models.Model):
    user = models.OneToOneField(User)
    follows = models.ManyToManyField('self', related_name='followed_by', symmetrical=False)

另外，如果我使用以下命令在shell中创建它：

tim, c = User.objects.get_or_create(username='tim')
chris, c = User.objects.get_or_create(username='chris')
tim.userfollowing.follows.add(chris.userfollowing)

shell退出给出错误：

fest.models.DoesNotExist: User has no userfollowing.

代码有什么问题？

Answer 1

在设置follow属性之前，您是否创建了一个与用户关联的UserFollowing对象？

即：

假设你有模特：

from django.db import models

class Place(models.Model):
    name = models.CharField(max_length=50)
    address = models.CharField(max_length=80)

    # On Python 3: def __str__(self):
    def __unicode__(self):
        return u"%s the place" % self.name

class Restaurant(models.Model):
    place = models.OneToOneField(Place, primary_key=True)
    serves_hot_dogs = models.BooleanField()
    serves_pizza = models.BooleanField()

    # On Python 3: def __str__(self):
    def __unicode__(self):
        return u"%s the restaurant" % self.place.name

您可以输入shell：

>>> p1 = Place(name='Demon Dogs', address='944 W. Fullerton')
>>> p1.save()
>>> r = Restaurant(place=p1, serves_hot_dogs=True, serves_pizza=False)
>>> r.save()

>>> # accessing the restaurant as a property of the place
>>> p1.restaurant
<Restaurant: Demon Dogs the restaurant>

有关详细信息，请参阅https://docs.djangoproject.com/en/dev/topics/db/examples/one_to_one/

跟随用户在Django，Admin UI中使用twitter

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