Question

所以我有一张桌子可以确定分支的区域代码，具体取决于月，
让我们来自January to february it's Region code would be 1, from February to March it would be 2和for the month of april upto date would be 3

所以这是表格的样本外观 enter image description here

我有一个从表中获取数据的代码，但我想要实现的是，如果所选数据的LoanDate在上面的日期内（在fld_Datefrom和fld_Dateto之间），它将使用指示的fld_BranchRegion以上。（例如，日期的Loandate为2013-01-12 00:00:00，如上所示，它将使用RegionCode 4A ，如果数据为2013-02-04 00:00:00，则会使用区域代码 3

这是我使用的代码

SELECT 
       TE.LOAN
       ,bp.REGION
       ,BP.ID
       ,TE.AMOUNT 
       ,te.ID       
FROM #TrackExpired TE
    inner join Transactions.TBLMAIN PM
    on TE.ID = PM.ID
    inner join #track BP
    on BP.ID=cast(TE.ID/1000000000000 as decimal(38,0))
WHERE ((cast(TE.EXPIRATION as date) < cast(TE.newloandate as date)) 
      OR(TE.NewLoanDate is null and (cast(TE.EXPIRATION as date) < cast(PM.REDEEMED as date))) or ((TE.NewLoanDate is null and PM.REDEEMED is null) and (PM.STATUS = 7 or PM.STATUS = 5))  )

这个问题是它生成重复值，所以我在 #track 表中有3次出现日期，数据的数量也输出3次，区别代码不同!! / p>

我希望从**＃track 中选择区域代码，而不是输出它们。根据数据的贷款日期。**

我只是希望实现这一点而不是输出所有区域代码，它只使用基于提供的 #track 表的范围之间的区域代码。

任何帮助？或其他方法？谢谢！。对不起，我是SQL新手。

编辑这里是创建临时表的代码。

#trackexpired

 SELECT PH.ID
      ,PH.LOAN
      ,PH.EXPIRATION
      ,PH.AMOUNT
      ,(SELECT T3.LOAN FROM Transactions.HISTO T3 INNER JOIN 
              (
                        SELECT MIN(T2.ID) as pawnhisto 
                        FROM Transactions.HISTO T2 
                        WHERE T2.ID > PH.ID
                            AND PH.ID = T2.ID
              ) T4
                        ON T4.pawnhisto = T3.ID

      )as 'NewLoanDate' 
INTO #TrackExpired
FROM Transactions.HISTO PH
    INNER JOIN Transactions.MAIN PM
    ON PM.ID=PH.ID
WHERE YEAR(PH.LOAN) = @YEAR

#track

   Select  bt.CODE
        ,bp.ID
        ,AREA
        ,REGION
        ,NCODE
        ,FROM
        ,isnull(fld_Dateto,GETDATE()) as fld_Dateto
 into #sort
 from Transactions.tbl_BranchTracking bt
 inner join Reference.tbl_BranchProfiles bp
 on bt.CODE = bp.CODE

 Select * into #track from #sort
 where @YEAR >= year(FROM)
        and
      @YEAR <= year(fld_Dateto)

Answer 1

测试数据

create table #LoanTable (
  ID  int not null,
  RegionCode nvarchar(50) not null,
  LoanDate datetime not null
  );

insert into #LoanTable values
(1,'5','10/01/2014'),
(2,'5','10/18/2014'),
(3,'5','10/02/2014'),
(4,'3','04/11/2014'),
(5,'3','04/05/2014'),
(6,'4A','01/09/2014'),
(7,'4A','01/05/2014')

create table #LoanDetailsTable (
  ID  int not null,
  LoanAmount INT not null,
  LoanDate datetime not null
  );

  insert into #LoanDetailsTable values
(1,5000,'10/15/2014'),
(2,1000,'10/11/2014'),
(3,2000,'10/09/2014'),
(4,1500,'04/13/2014'),
(5,5000,'04/17/2014'),
(6,500,'01/19/2014'),
(7,2500,'01/15/2014')

<强>查询

;With RegCode
AS
 (
    SELECT RegionCode, MAX(MONTH(LoanDate)) [Month]
    FROM #LoanTable
    GROUP BY RegionCode
 )
SELECT LDT.* , RC.RegionCode
FROM #LoanDetailsTable LDT INNER JOIN RegCode RC
ON MONTH(LDT.LoanDate) = RC.[Month]

<强>结果

ID  LoanAmount  LoanDate                  RegionCode
1   5000        2014-10-15 00:00:00.000       5
2   1000        2014-10-11 00:00:00.000       5
3   2000        2014-10-09 00:00:00.000       5
4   1500        2014-04-13 00:00:00.000       3
5   5000        2014-04-17 00:00:00.000       3
6   500         2014-01-19 00:00:00.000       4A
7   2500        2014-01-15 00:00:00.000       4A

使用CTE提取日期的月份部分以及与之关联的区域代码，然后将其与贷款日期月份的数据表和cte中提取的月份一起加入，并获取当时的区域代码。快乐的日子:)）

每月选择特定数据

1 个答案: