Question

我收到以下错误，我不知道它为什么会发生。我想知道是否还有其他人可以对这个问题有所了解。

12-25 22:52:50.252: E/AndroidRuntime(813): Caused by: java.lang.IllegalArgumentException: Cannot bind argument at index 1 because the index is out of range.  The statement has 0 parameters.
12-25 22:52:50.252: E/AndroidRuntime(813):  at android.database.sqlite.SQLiteProgram.bind(SQLiteProgram.java:212)
12-25 22:52:50.252: E/AndroidRuntime(813):  at android.database.sqlite.SQLiteProgram.bindString(SQLiteProgram.java:166)
12-25 22:52:50.252: E/AndroidRuntime(813):  at android.database.sqlite.SQLiteProgram.bindAllArgsAsStrings(SQLiteProgram.java:200)
12-25 22:52:50.252: E/AndroidRuntime(813):  at android.database.sqlite.SQLiteDirectCursorDriver.query(SQLiteDirectCursorDriver.java:47)
12-25 22:52:50.252: E/AndroidRuntime(813):  at android.database.sqlite.SQLiteDatabase.rawQueryWithFactory(SQLiteDatabase.java:1314)
12-25 22:52:50.252: E/AndroidRuntime(813):  at android.database.sqlite.SQLiteDatabase.queryWithFactory(SQLiteDatabase.java:1161)
12-25 22:52:50.252: E/AndroidRuntime(813):  at android.database.sqlite.SQLiteDatabase.query(SQLiteDatabase.java:1032)
12-25 22:52:50.252: E/AndroidRuntime(813):  at android.database.sqlite.SQLiteDatabase.query(SQLiteDatabase.java:1200)

代码在这里：

public Player getPlayer(String name) {
    SQLiteDatabase db = this.getReadableDatabase();

    String[] projection = {
            PlayerEntry.COLUMN_NAME_PLAYER_NAME,
            PlayerEntry.COLUMN_NAME_PLAYED_GAMES,
            };

    String selection =  PlayerEntry.COLUMN_NAME_PLAYER_NAME ;
    String[] selectionArgs = new String[1];
    selectionArgs[0] = name;

    Cursor cursor = db.query(
            PlayerEntry.TABLE_NAME,  // The table to query
            projection,                               // The columns to return
            selection,                                // The columns for the WHERE clause
            selectionArgs,                            // The values for the WHERE clause
            null,                                     // don't group the rows
            null,                                     // don't filter by row groups
            null                                 // The sort order
            );

    if (cursor != null)
        cursor.moveToFirst();

Answer 1

selection应该是一个表达式，selectionArgs应该包含与?中selection个文字占位符一样多的元素。

您的selection不是表达式，没有任何?，但您在selectionArgs中有一个元素。

您可能需要以下内容：

String selection =  PlayerEntry.COLUMN_NAME_PLAYER_NAME + "=?";

使其成为与selectionArgs[0]中绑定的文字再次匹配玩家名称列的表达式。

Answer 2

在我的情况下，我在单引号内有问号，例如“？”。删除单引号可以解决该错误。

摘自上述theblang的评论。

SQLite：无法绑定索引1处的参数，因为索引超出范围。该语句有0个参数

2 个答案: