Question

这是我的数据库结构：

CREATE TABLE `rs_payment` (
  `id` int(11) NOT NULL AUTO_INCREMENT,
  `amount` int(11) NOT NULL DEFAULT '0',
  `user_fid` int(11) NOT NULL,
  `payment_created_date` timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP,
  `payment_end_date` timestamp NULL DEFAULT NULL,
  PRIMARY KEY (`id`),
  KEY `user_fid` (`user_fid`),
  CONSTRAINT `rs_payment_ibfk_1` FOREIGN KEY (`user_fid`) REFERENCES `rs_user` (`id`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8;

CREATE TABLE `rs_payment_to_complex` (
  `id` int(11) NOT NULL AUTO_INCREMENT,
  `payment_fid` int(11) NOT NULL,
  `complex_fid` int(11) NOT NULL,
  PRIMARY KEY (`id`),
  KEY `payment_fid` (`payment_fid`),
  KEY `complex_fid` (`complex_fid`),
  CONSTRAINT `rs_payment_to_complex_ibfk_2` FOREIGN KEY (`complex_fid`) REFERENCES `rs_complex` (`id`),
  CONSTRAINT `rs_payment_to_complex_ibfk_1` FOREIGN KEY (`payment_fid`) REFERENCES `rs_payment` (`id`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8;

CREATE TABLE `rs_user` (
  `id` int(11) NOT NULL AUTO_INCREMENT,
  `email` varchar(258) NOT NULL,
  `password` text NOT NULL,
  PRIMARY KEY (`id`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8;

CREATE TABLE `rs_complex` (
  `id` int(11) NOT NULL AUTO_INCREMENT,
  `name` text NOT NULL,
  `reservation_schedule` tinyint(4) NOT NULL DEFAULT '1',
  PRIMARY KEY (`id`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8;

这些是我在PaymentToComplex模型中的关系：

public function relations()
{
    return array(
        'complexF' => array(self::BELONGS_TO, 'Complex', 'complex_fid'),
        'paymentF' => array(self::BELONGS_TO, 'Payment', 'payment_fid'),
        'userF' => array(self::BELONGS_TO, 'User', 'payment_fid'),
        //'userF' => array(self::BELONGS_TO, 'User', 'paymentF.user_fid'),
    );
}

复杂和支付关系运作良好。用户关系实际上已加入查询，如下所示：LEFT OUTER JOIN rs_user userF ON (t.payment_fid=userF.id)。

我需要更新userF的外键以加入user_fid表的rs_payment列。注释代码不起作用。

感谢您的帮助。

Answer 1

您应该使用CActiveRecord::through使用userF获取paymentF，如下所示：

'userF' => array(self::BELONGS_TO, 'User', array('user_fid'=>'id'),'through'=>'paymentF'),

更多http://www.yiiframework.com/doc/guide/1.1/en/database.arr#relational-query-with-through

Yii CActiveRecord关系的外键关系

1 个答案: