Question

[固定] 我解决了我的问题。根据{{3}}的建议，我访问了Fred -ii-。我看到他使用的复选框似乎比按钮更有用，因为你可以一次取出多个物体。他还将对象的id附加到按钮上，就像this Q&A on SO建议的那样。

<form action="" method='POST'> <input style='display:block; margin:0 auto;'type='submit' name='delete_button' value='<?php echo row['id']; ?>'/> </form>

这是固定代码。我现在可以单独删除这些框。谢谢你提出的所有建议。我现在也在使用mysqli。

$query = mysqli_query($connect, "SELECT * FROM shouts ORDER BY `id` DESC LIMIT 5") or die('<p id="formbox" style="text-align:center;">There was an unexpected error grabbing news from the database</p>');

    while ($row = mysqli_fetch_array($query)) {
        $title2 = $row['title'];
        $post2 = $row['post'];
        $date2 = $row['date'];
        $author = $row['author'];

        echo '<div class="news-title"><b style="float:left;">'.$author.'</b><b style="text-align:center; color:green;">'.$title2.'</b><a href="">'.$date2.'</a></div>';
        echo '<div class="news-body">'.$post2.'</div>';
        if (isset($_SESSION['username']) && ($_SESSION['level'] >= 3 || $_SESSION['group'] == 'Admin')) {
            ?>
            <form action="" method='POST'>
            <input style='display:block; margin:0 auto;'type='submit' name='delete_button[]' value="<?php echo $row['id']; ?>"/>
            </form>
            <?php
        }
        echo '<br>';
    }
    if(isset($_POST['delete_button'])) { 
    $boxid = $_POST['delete_button'];
    for($i=0;$i<count($boxid);$i++){
        $del_id = $boxid[$i];
        mysqli_query($connect, "DELETE FROM `shoutbox`.`shouts` WHERE `shouts`.`id` = '$del_id'") or die('<p id="formbox" style="text-align:center;">There was an unexpected error deleting the post from the database</p>');
        }
    }

[问题] 所以目前我一直在为一个网站工作，仅仅是为了我的学习目的而谷歌到目前为止一直都是很好的帮助。虽然，我似乎无法解决这个问题。我有一个“新闻提要”

Subin

它不允许我发布图像，但它是我能给出的唯一视觉想法。除非您想访问我的主页http://i.stack.imgur.com/oieXJ.png，否则新闻Feed就在那里，当然没有删除按钮。

我想为每个帖子添加一个“删除”按钮，以便我可以在需要时单独删除它们。我正在使用当前代码的问题。它从数据库中删除所有这些，但我只想删除我点击删除的“帖子”。这是我的来源：

$query = mysql_query("SELECT * FROM shouts ORDER BY `id` DESC LIMIT 5") or die('<p id="formbox" style="text-align:center;">There was an unexpected error grabbing news from the database</p>');

    while ($row = mysql_fetch_array($query)) {
        $title2 = $row['title'];
        $post2 = $row['post'];
        $date2 = $row['date'];
        $author = $row['author'];
        $boxid = $row['id'];

        echo '<div class="news-title"><b style="float:left;">'.$author.'</b><b style="text-align:center; color:green;">'.$title2.'</b><a href="">'.$date2.'</a></div>';
        echo '<div class="news-body">'.$post2.'</div>';
        if ($_SESSION['level'] > 3 || $_SESSION['group'] == 'Admin' || $_SESSION['group'] == 'Owner') {
            ?>
            <form action="" method='post'>
            <input style='display:block; margin:0 auto;'type='submit' name='delete_button' value='Delete' />
            </form>
            <?php
        if(isset($_POST['delete_button'])) { 
        $con = mysql_query("DELETE FROM `shoutbox`.`shouts` WHERE `shouts`.`id` = '$boxid'") or die('<p id="formbox" style="text-align:center;">There was an unexpected error deleting the post from the database</p>');
        header('refresh:1; url=/');
        mysql_close($con);
    }
        }
        echo '<br>';
    }

我是PHP HTML CSS MYSQL的新手。我对所有建议和评论持开放态度。任何帮助将不胜感激，谢谢。

Answer 1

首先，您要选择多行：

mysql_query("SELECT * FROM shouts ORDER BY `id` DESC LIMIT 5")

然后你要为每一行抓取一个数组

while ($row = mysql_fetch_array($query)) {

然后为该行设置boxid，然后在该行的循环内运行删除查询，其中WHERE子句查找该boxid。

因此，给定此代码流程，您将始终删除表中的所有行。

mysql_query("DELETE FROM `shoutbox`.`shouts` WHERE `shouts`.`id` = '$boxid'")

现在，真正的问题是，如何解决这个问题？

在你的select语句中，只需添加一个where子句，它只返回带有boxid的行或你实际需要的任何id，这样就只返回一行（或者确切地说是要删除的行）

"SELECT FROM `shoutbox`.`shouts` WHERE `shouts`.`id` = '$someSortOfID'"

此外，不推荐使用mysql_ *，因此please see the following documentation关于如何“升级”新标准mysqli。

Answer 2

我建议你不要使用折旧的 mysql _ * 功能!!!!!

您需要做的是将输入值更改为行ID ：

<form action="" method='POST'>
 <input style='display:block; margin:0 auto;'type='submit' name='delete_button' value='<?echo$boxid;?>' />
</form>

然后在while循环之外移动 if（isset（$ _ POST ['delete_button']））中的整个代码，整个代码将是：

<?php
$query = mysql_query("SELECT * FROM shouts ORDER BY `id` DESC LIMIT 5") or die('<p id="formbox" style="text-align:center;">There was an unexpected error grabbing news from the database</p>'); 
while ($row = mysql_fetch_array($query)) {
 $title2 = $row['title'];
 $post2 = $row['post'];
 $date2 = $row['date'];
 $author = $row['author'];
 $boxid = $row['id'];

 echo '<div class="news-title"><b style="float:left;">'.$author.'</b><b style="text-align:center; color:green;">'.$title2.'</b><a href="">'.$date2.'</a></div>';
 echo '<div class="news-body">'.$post2.'</div>';
 if ($_SESSION['level'] > 3 || $_SESSION['group'] == 'Admin' || $_SESSION['group'] == 'Owner') {
?>
 <form action="" method='post'>
  <input style='display:block; margin:0 auto;'type='submit' name='delete_button' value='<?echo$boxid;?>' />
 </form>
<?php
 }
 echo '<br>';
}
if(isset($_POST['delete_button'])) { 
 $boxid = $_POST['delete_button'];
 $con = mysql_query("DELETE FROM `shoutbox`.`shouts` WHERE `shouts`.`id` = '$boxid'") or die('<p id="formbox" style="text-align:center;">There was an unexpected error deleting the post from the database</p>');
 header('Location: http://'.$_SERVER['HTTP_HOST']);
 mysql_close($con);
}
?>

PHP MySQL通过附加到“对象”的删除按钮从数据库中删除行

2 个答案: