此代码是我的应用的主页。对于这个应用程序,我想创建启动。
主要应用代码: -
package com.Wase.edittext;
import java.util.Timer;
import java.util.TimerTask;
import android.app.Activity;
import android.content.Intent;
import android.os.Bundle;
import android.text.format.Time;
import android.widget.EditText;
public class Splash extends Activity {
Timer timer = new Timer();
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.splash_logo);
Time.schedule(new TimerTask() {
public void run() {
Intent intent = new Intent(Splash.this, MyAndroidAppActivity.class);
startActivity(intent);
finish();
}
}, 5000);
}
}
这是我的启动代码..请看错误并告诉我..
答案 0 :(得分:0)
首先创建一个新的XML文件并使用您想要的任何设计,然后创建活动(java)文件并使用下面的代码并根据您的要求更改您的屏幕和变量名称。
public class Splash extends Activity {
Timer timer = new Timer();
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.splash);
timer.schedule(new TimerTask() {
public void run() {
Intent intent = new Intent(Splash.this, MyAndroidAppActivity.class);
startActivity(intent);
finish();
}
}, 5000);
}
}
这是你的splash.xml
<RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android"
xmlns:tools="http://schemas.android.com/tools"
android:id="@+id/splash"
android:layout_width="match_parent"
android:layout_height="match_parent"
android:background="#FFFFFF"
tools:context=".IMyCompany" >
<ImageView
android:id="@+id/imageView1"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:layout_alignParentTop="true"
android:layout_centerHorizontal="true"
android:layout_marginTop="153dp"
android:src="@drawable/logo" />
</RelativeLayout>
它将在5秒后移至新活动。
答案 1 :(得分:0)
public class SplashScreen extends Activity {
public SplashScreen instance;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.xml_splashscreen);
if (instance != null) {
instance.finish();
}
instance = this;
Thread threadMenu = new Thread(new Runnable() {
public void run() {
try {
// sleep 3 second and go next page
Thread.sleep(400);
// Check Vefication Success then Load HomeScreen Check
Intent splash = new Intent(getBaseContext(),
MyAndroidAppActivity .class);
startActivity(splash);
finish();
overridePendingTransition(R.anim.push_in_from_left,
R.anim.push_out_to_right);
}
} catch (InterruptedException e) {
e.printStackTrace();
}
}
});
threadMenu.start();
}
}
清单文件中的:
<activity
android:name="com.demo.SplashScreen"
android:label="@string/app_name"
android:screenOrientation="sensorPortait" >
<intent-filter>
<action android:name="android.intent.action.MAIN" />
<category android:name="android.intent.category.LAUNCHER" />
</intent-filter>
</activity>
<activity
android:name=".com.demo.MyAndroidAppActivity"
android:configChanges="keyboardHidden"
android:screenOrientation="sensorPortait"
android:windowSoftInputMode="stateHidden" />
答案 2 :(得分:0)
use this code
====
public class SplashScreenActivity extends Activity {
final int splashTimeOut = 3000;
ImageView imgSplash;
/** Called when the activity is first created. */
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.splashscreen);
imgSplash = (ImageView) findViewById(R.id.imgsplash);
setContentBasedOnLayout();
// TODO Auto-generated method stub
Thread splashThread = new Thread() {
int wait = 0;
@Override
public void run() {
try {
super.run();
while (wait < splashTimeOut) {
sleep(100);
wait += 100;
}
} catch (Exception e) {
e.printStackTrace();
} finally {
//If You Want To Do Something Write Here Your Code
}
}
};
splashThread.start();
}
public boolean onKeyDown(int keyCode, KeyEvent event) {
if (keyCode == KeyEvent.KEYCODE_BACK) {
return true;
}
return super.onKeyDown(keyCode, event);
}
}