我有以下数组(地图):
Map<String, String[]> fields = new HashMap<String, String[]>();
fields.put( "memberDOB", new String[]{ "true", "", "", "2", "date"} );
fields.put( "memberDOJ", new String[]{ "true", "", "", "2", "date"} );
fields.put( "membershipDate", new String[]{ "true", "", "", "2", "date"} );
fields.put( "txtAccountNo", new String[]{ "true", "1", "10", "1", "int"} );
fields.put( "txtMemIntro1Address", new String[]{ "true", "5", "", "1", "string"} );
validate validateF = new validate();
if(validateF.validate_fields(fields)){
//validated
}
检索值和键:
public boolean validate_fields(Map<String, String[]> fields) {
//How to loop through each key
return true;
}
答案 0 :(得分:1)
您可以使用:
for (String key : fields.keySet()) {
// key iterate over all keys in fields
}
答案 1 :(得分:1)
Iterator iterator=fields.keySet().iterator();
while(iterator.hasNext()) {
iterator.next();
// logic here
}
此外,您可以按照以下方式迭代值和键入
for (Map.Entry<String, String[]> entry : map.entrySet()) {
System.out.println("Key : " + entry.getKey() + " Value : "
+ entry.getValue());
}
答案 2 :(得分:1)
Java自1.5以来每次迭代都有, 所以你可以像这样循环每个键:
for (String key : fields.keySet()) {
String[] value = fields.get(key);
// process the value
}