Question

假设我的xml响应如下：

<soap:Envelope xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
   <soap:Body>
      <GetCitiesByCountryResponse xmlns="http://www.webserviceX.NET">
         <GetCitiesByCountryResult><![CDATA[<NewDataSet>
  <Table>
    <Country>British Indian Ocean Territory</Country>
    <City>Diego Garcia</City>
  </Table>
  <Table>
    <Country>India</Country>
    <City>Ahmadabad</City>
  </Table>
  <Table>
    <Country>India</Country>
    <City>Akola</City>
  </Table>
  <Table>
    <Country>India</Country>
    <City>Aurangabad</City>
  </Table>

在这里，我希望使用SoapUi groovy脚本从包含<Country>的根节点<Table>名称获取<City>元素值作为“Akola”。

Answer 1

这样的东西？

import com.eviware.soapui.support.XmlHolder
def testCase = messageExchange.modelItem.testCase
def responseHolder = new XmlHolder(messageExchange.getResponseContentAsXml());
def resultFromServer = responseHolder["//Table/City[text()='Akola']/ancestor::Table[1]/Country/text()"]

Answer 2

你也可以试试这个：

## set option to use digits for seconds
options(digits.secs = 2)
## convert your factor to a string and then to Posix format
tmp <- strptime(as.character(data$Time),'%H:%M:%OS')
## convert it to a numeric (unit seconds)
as.numeric(strftime(tmp,'%OS'))+60*as.numeric(strftime(tmp,'%M'))+60*60*as.numeric(strftime(tmp,'%H'))

如何使用soap ui中的groovy脚本获取包含具有特定值的元素的xml根节点

2 个答案: